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hammer [34]
3 years ago
8

Tommy purchased a riding lawnmower with an original value of $2,500. If the value of the riding lawnmower decreases by $300 per

year, what should be the value of the lawnmower after five years?
Mathematics
2 answers:
Eva8 [605]3 years ago
7 0

Answer:

$1000.

Step-by-step explanation:

Let x represent number of years.

We have been given that Tommy purchased a riding lawnmower with an original value of $2,500. The value of the riding lawnmower decreases by $300 per year. We are asked to find the value of lawnmower after 5 years.

Since the value of the riding lawnmower decreases by $300 per year, so value of lawnmower decrease in 5 years would be 5 times $300.

The final value of lawnmower would be initial value minus value decreased in 5 years.

\text{The value of the lawnmower after five years}=\$2500-\$300(5)

\text{The value of the lawnmower after five years}=\$2500-\$1500

\text{The value of the lawnmower after five years}=\$1000

Therefore, the value of lawnmower after  years would be $1000.

Margarita [4]3 years ago
5 0

Answer:

1000

Step-by-step explanation:

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A community pool that is shaped like a regular pentagon needs a new cover for the winter months. The radius of the pool is 20.10
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Answer:

960.42\text{ ft}^2

Step-by-step explanation:

Please find the attachment.  

We have been given that a community pool that is shaped like a regular pentagon needs a new cover for the winter months.

To find the area of community pool we will use area of pentagon formula.

\text{Area of pentagon}=\frac{1}{2}a*p, where, a represents the apothem or perpendicular distance from the center of the pentagon and p represents perimeter of pentagon.

Let us find the perimeter of our given pentagon by multiplying each side length by 5.

\text{Perimeter of community pool}=5\times 23.62

\text{Perimeter of community pool}=118.1

Now let us find apothem of our pentagon by using Pythagoras theorem.  

a^2=20.10^2-11.81^2

a^2=404.01-139.4761

a^2=264.5339

a=\sqrt{264.5339}

a=16.2645

Upon substituting our given values in above formula we will get,

\text{Area of community pool}=\frac{1}{2}\times 16.2645\times 118.1

\text{Area of community pool}=8.13224907\times 118.1

\text{Area of community pool}=960.418615627971\approx 960.42

Therefore, the area of the pool that needs to be covered is 960.42 square feet.

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