Answer:

Step-by-step explanation:
![{x}^{ - 2} {y}^{3} \sqrt[3]{ 64{x}^{5} {y}^{3} } = a {x}^{b} {y}^{c} \\ \\ {x}^{ - 2} {y}^{3} \times 4 \times {x}^{ \frac{5}{3} } \times y= a {x}^{b} {y}^{c} \\ \\ 4 {x}^{ \frac{5}{3} - 2 } {y}^{3 + 1} = a {x}^{b} {y}^{c} \\ \\ 4 {x}^{ \frac{5 - 6}{3} } {y}^{4} = a {x}^{b} {y}^{c} \\ \\ 4 {x}^{ \frac{ - 1}{3} } {y}^{4} = a {x}^{b} {y}^{c} \\ \\ equating \: like \: terms \: on \: both \: sides \\ \\ a = 4 \\ \\ b = - \frac{1}{3} \\ \\ c = 4 \\ \\ abc = 4 \times ( - \frac{1}{3} ) \times 4 \\ \\ = 16 \times ( - \frac{1}{3} ) \\ \\ abc = - \frac{16}{3}](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B%20-%202%7D%20%20%7By%7D%5E%7B3%7D%20%20%5Csqrt%5B3%5D%7B%2064%7Bx%7D%5E%7B5%7D%20%20%7By%7D%5E%7B3%7D%20%7D%20%20%3D%20a%20%7Bx%7D%5E%7Bb%7D%20%20%7By%7D%5E%7Bc%7D%20%20%5C%5C%20%20%5C%5C%20%20%7Bx%7D%5E%7B%20-%202%7D%20%20%7By%7D%5E%7B3%7D%20%20%20%5Ctimes%204%20%5Ctimes%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B5%7D%7B3%7D%20%7D%20%20%20%5Ctimes%20y%3D%20a%20%7Bx%7D%5E%7Bb%7D%20%20%7By%7D%5E%7Bc%7D%20%20%20%5C%5C%20%20%5C%5C%204%20%7Bx%7D%5E%7B%20%5Cfrac%7B5%7D%7B3%7D%20-%202%20%7D%20%20%7By%7D%5E%7B3%20%2B%201%7D%20%20%3D%20a%20%7Bx%7D%5E%7Bb%7D%20%20%7By%7D%5E%7Bc%7D%20%20%20%5C%5C%20%20%5C%5C%204%20%7Bx%7D%5E%7B%20%5Cfrac%7B5%20-%206%7D%7B3%7D%20%7D%20%20%7By%7D%5E%7B4%7D%20%20%3D%20a%20%7Bx%7D%5E%7Bb%7D%20%20%7By%7D%5E%7Bc%7D%20%20%20%5C%5C%20%20%5C%5C%204%20%7Bx%7D%5E%7B%20%5Cfrac%7B%20-%201%7D%7B3%7D%20%7D%20%20%7By%7D%5E%7B4%7D%20%20%3D%20a%20%7Bx%7D%5E%7Bb%7D%20%20%7By%7D%5E%7Bc%7D%20%20%20%5C%5C%20%20%5C%5C%20equating%20%5C%3A%20like%20%5C%3A%20terms%20%5C%3A%20on%20%5C%3A%20both%20%5C%3A%20sides%20%5C%5C%20%20%5C%5C%20a%20%3D%204%20%5C%5C%20%20%5C%5C%20b%20%3D%20%20%20-%20%5Cfrac%7B1%7D%7B3%7D%20%20%5C%5C%20%20%5C%5C%20c%20%3D%204%20%5C%5C%20%20%5C%5C%20abc%20%3D%204%20%5Ctimes%20%28%20-%20%20%5Cfrac%7B1%7D%7B3%7D%20%29%20%5Ctimes%204%20%5C%5C%20%20%5C%5C%20%20%3D%2016%20%5Ctimes%20%28%20-%20%20%5Cfrac%7B1%7D%7B3%7D%20%29%20%5C%5C%20%20%5C%5C%20abc%20%3D%20%20-%20%20%5Cfrac%7B16%7D%7B3%7D%20)
First you need to know the prime numbers from 1-10.
They are 2, 3, 5, 7,
1st draw: P(prime) = 4/10
2nd draw: P(prime) = 3/9
Multiply these numbers 12/90 = 2/15
Answer:
because the 1st corner and the 2nd corner is places in a straight line which the total agle is 180° so since the 1st corner has same angle as the 13th one the 14th is must be have same angle as the 2nd corner. so that the 1st corner + the 14th corner is equal as 180°
Answer:
Yes
Step-by-step explanation:
To figure out if (1,2) is a solution to the system, we can plug the values in and see if it is true.
3x-2y=-1
3(1)-2(2)=-1
3-4=-1
-1=-1
It is true for this equation. Now let's check the next one.
y=-x+3
2=-(1)+3
2=2
Since both equations are true when we plug the values in, (1,2) is a solution to the system.