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3 years ago

Which other angles could be in that triangle?

Mathematics

1 answer:

CaHeK987 [17]3 years ago

7 0

The other angles in the isosceles triangle with an angle of 100° will be 40°

Step-by-step explanation:

Lets define an isosceles triangle first.

"An isosceles triangle is a triangle with two equal sides and two equal angles.

Given that an angle of the triangle is 100°

We know that the sum of internal angles of a triangle is 180°

The sum of remaining two angles is:

=180°-100°

=80°

As the triangle is an isosceles triangle, the two angles will be equal.

So the angles will be:

$=\frac{80}{2}\\=40$

The other angles in the isosceles triangle with an angle of 100° will be 40°

Keywords: Triangle, isosceles triangle

Learn more about isosceles triangle at:

#LearnwithBrainly

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2 years ago

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Use this graph of velocity vs. time for two objects to answer the question.

Lynna [10]

Using derivatives, it is found that the correct option is:

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In this problem:

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The <u>change in velocity for object C is greater</u>, thus, it has a greater acceleration, and the correct option is:

A. Object C has an acceleration that is greater than the acceleration for D.

A similar problem is given at brainly.com/question/14516604

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2 years ago

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the diagonal of a rectangle is 16 inches. if the height of the rectangle is 8 inches. what is the length of the rectangle?

Yakvenalex [24]

Answer:

Length: 13.9 inches

Step-by-step explanation:

a^2 + b^2 = c^2

a = 8 and c= 16

8^2 + b^2 = 16^2

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2 years ago

Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon

Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

$h(t)=-16t^2+40t+5$

we know that

When the ball hits the ground, the height is equal to zero

$-16t^2+40t+5=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$

is equal to

$t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+40t+5=0$

$a=-16\\b=40\\c=5$

substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

$t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec$

therefore

The solution is t=2.62 seconds

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2 years ago

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Anuta_ua [19.1K]

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Step-by-step explanation:

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3 years ago