Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.
ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.
Answer:
A.
C.
Step-by-step explanation:
Given:
The given line is
Express this in slope-intercept form , where m is the slope and b is the y-intercept.
Therefore, the slope of the line is .
Now, for perpendicular lines, the product of their slopes is equal to -1.
Let us find the slopes of each lines.
Option A:
On comparing with the slope-intercept form, we get slope as .
Now, . So, option A is perpendicular to the given line.
Option B:
For lines of the form , where, a is a constant, the slope is undefined. So, option B is incorrect.
Option C:
On comparing with the slope-point form, we get slope as .
Now, . So, option C is perpendicular to the given line.
Option D:
On comparing with the slope-intercept form, we get slope as .
Now, . So, option D is not perpendicular to the given line.