Question

Given the equation P2 = A3, what is the orbital period, in years, for the planet Saturn? (Saturn is located 9.5 AU from the sun.)

Answer 1

Answer: 29.28 years

Explanation:

From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body  it is revolving about.

P² =A³

Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)

It is given that, For Saturn, A = 9.5 AU. We need to find P

⇒P² = (9.5 AU)³

⇒P² = 857.38

⇒P = 29.28 years

Thus, the orbital period of Jupiter is 29.28 years around the Sun.