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dsp73
2 years ago
14

A meteorologist found that the rainfall in Vindale during the first half of the month was 1/2 of an inch. At the end of the mont

h, she found that the total rainfall for the month was 2/3 of an inch. How much did it rain in the second half of the month?
Mathematics
1 answer:
DochEvi [55]2 years ago
3 0

The quantity of rainfall that fell in the second half of the month is; ¹/₆ of an inch.

<h3>How to solve fraction word problems?</h3>

We are given;

Rainfall during first half of the month = 1/2 inch

Total rainfall for the month = 2/3 inch

Now, to find the rainfall for the second half of the month, we just subtract the one for the first half from the one for the month to get;

Rainfall in second half of the month = ²/₃ - ¹/₂ = ¹/₆ inches

Read more about Fraction Word Problems at; brainly.com/question/11562149

#SPJ1

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*Please I need help quickly* Approximate the mean of the frequency distribution for the ages of the residents of a town.
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Answer:

The mean age of the frequency distribution for the ages of the residents of a town is 43 years.

Step-by-step explanation:

We are given with the following frequency distribution below;

 

     Age                      Frequency (f)               X                    X \times f

     0 - 9                            30                         4.5                   135

    10 - 19                           32                        14.5                  464

    20 - 29                         12                         24.5                 294

    30 - 39                         20                        34.5                 690

    40 - 49                         25                        44.5                1112.5

    50 - 59                         53                        54.5                2888.5

    60 - 69                         49                        64.5                3160.5

    70 - 79                          13                         74.5                968.5

    80 - 89                  <u>        8        </u>                  84.5         <u>        676        </u>

    Total                      <u>      242      </u>                                  <u>      10389      </u>

Now, the mean of the frequency distribution is given by the following formula;

                          Mean =  \frac{\sum X \times f}{\sum f}

                                     =  \frac{10389}{242}  = 42.9 ≈ 43 approx.

Hence, the mean age of the frequency distribution for the ages of the residents of a town is 43 years.

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