All categories

3 years ago

So I need to put them in the order can you please help me

Mathematics

1 answer:

Alex787 [66]3 years ago

4 0

Answer:

2.112

Step-by-step explanation:

don't have one

You might be interested in

Which representation has the greatest rate of change?

Zinaida [17]

Answer:

Is it health club c for the second one?

Step-by-step explanation:

6 0

1 year ago

Read 2 more answers

Is the GCF (greatest common factor) of a pair of numbers ever equal to one of the numbers? Explain why or why not.

FrozenT [24]

Answer:

Yes

Step-by-step explanation:

Yes, that is possible because whenever one number is a factor of the other one, it's their greatest common factor. Here are some examples.

2 and 200

10 and 100

13 and 52

one thousand and one million

7 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min, and its coarseness is such that it forms a pile in the shap

pogonyaev

Answer:

Rate of increase in height = $\frac{dh}{dt}=0.3156ft/min$

Step-by-step explanation:

we know that volume of a cone is given by

$V=\frac{1}{12}\pi d^{2}h$

It is Given that diameter equals height thus we have

$V=\frac{1}{12}\pi h^{2}h\\\\V=\frac{1}{12}\pi h^{3}$

Differentiating both sides with respect to time we get

$\frac{dV}{dt}=\frac{1}{12}\pi \frac{dh^{3}}{dt}\\\\\frac{dV}{dt}=\frac{1}{12}\pi(3h^{2}\frac{dh}{dt})$

Applying values and solving for $\frac{dh}{dt}$ we get

$\frac{dh}{dt}=\frac{12\frac{dV}{dt}}{3\pi h^{2}}\\\\\frac{dh}{dt}=0.3156ft/min$

8 0

2 years ago

Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r

Rainbow [258]

Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>

Since the degree of given polynomial is 4
Therefore it must have four roots.
Already given that the given polynomial has 1 positive real root and 1 negative real root .
Every polynomial with degree greater than 1 has atleast one imaginary root.

<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

8 0

2 years ago

F(x)=12x2-4x-8. G(x)=11x-6

AlekseyPX

Answer: Second option.

Step-by-step explanation:

Given the functions f(x) and g(x):

$f(x)=12x^2-4x-8\\\\g(x)=11x-6$

You need to divide them in order to find $(\frac{f}{g})(x)$ asked in the exercise. Then:

$(\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}$

Now, it is important to remember that, by definition, the division by zero is not defined. Therefore, the denominator of the function cannot be zero.

Let's find the value of "x" for which the denominator of the function would be zero:

1. You need to make the denominator equal to zero:

$11x-6=0$

2. Finally, you must solve for "x":

$11x=6\\\\x=\frac{6}{11}$

Therefore, as you can see, the answer is:

$(\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}$ , $x=\frac{6}{11}$

4 0

2 years ago