Answer:
Step-by-step explanation:
Mathematically, we can calculate the slope
using the formula below;
m = (y2-y1)/(x2-x1)
Where (x1.y1) = (6,-8)
(x2, y2) = (3,-4)
So inputing these values into the formula, we have
m = (-4-(-8))/(3-6)
m = (-4+8)/-3 = 4/-3 = -4/3
Now, we want to write the equation of the line;
y= -4/3x + c
to get the value of c, we simply need to use any of the points. We use any of the two points by substituting the values of x and y at that point.
Let’s use (3,-4)
That would give ;
-4 = -4/3(3) + c
-4 = -4 + c
This means c = 0
Thus the equation of the line is y = -4/3x
Now to find out if the point (-3,4) is on the line
We only need to substitute the values of x and y here and see ;
Thus;
4 = -4/3(-3)
Sine 4 = 4
We can conclude that the point is on the line in question
72 I think it is I believe
Answer:
Step-by-step explanation:
Have a good day :)
Answer:
Step-by-step explanation:
y = 3 - 4ln(1 - x)
⇒ 
⇒ 
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1. Yes
2. No
3. 46.6 (recurring)
5. 22'
Sorry this is all I can do. Hope this helps :)
