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Mekhanik [1.2K]
3 years ago
6

What is the distance between two points located at (–6, 2) and (–6, 8) on a coordinate plane?"

Mathematics
1 answer:
ASHA 777 [7]3 years ago
3 0

Answer:

4 units

Step-by-step explanation:

X coordinate never changed so you just need to subtract 2 from 8 to see the unit difference.

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HELPPPP ME PLZZZZZZZ
MAXImum [283]

Answer:

It would take alot of time for be to fill everything out so the simple solution is, complementary angles add up to 90 degrees and supplementary add up to 180 degrees. Simply for complementary do 90 - m<1 = m<2, and for supplementary 180 - m<3 = m<4.

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3 years ago
A new computer can complete a complex biochemistry calculation in 7 hours less than an older-model computer. Working together, t
Alchen [17]
The rate a computer works is 1/time. Working together, you add the rates.
Let new computer be x, old computer be y.
x = y - 7

\frac{1}{x} + \frac{1}{y} = \frac{1}{13} \\  \\ \frac{1}{y-7}+\frac{1}{y} = \frac{1}{13} \\  \\ \frac{2y-7}{y(y-7)} = \frac{1}{13} \\  \\ y(y-7) = 13(2y-7) \\  \\ y^2-33y+91 = 0 \\  \\ y = 29.96 \\  \\ x = y-7 = 29.96-7 = 22.96
Rounded to nearest tenth gives:
x = 23 hours
6 0
3 years ago
What is the sum of the interior
frutty [35]
N is the amount of sides
sum=13 times 180 =2340
7 0
2 years ago
Help please multiply matrix D by matrix E.
aleksandr82 [10.1K]
It's going to be a 3x2. Im assuming its [ 5 10 on the first row, second row would be -2, -4, then the bottom row would be 1, 2] Hope I helped!

3 0
2 years ago
Read 2 more answers
Help please!posted picture of question
Evgen [1.6K]
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)

The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)

Answer: The system of inequalities would produce the region indicated on the graph is Option B

8 0
3 years ago
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