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3 years ago

Plzzz answer I will mark brainiest

Mathematics

1 answer:

slava [35]3 years ago

6 0

Answer:

perimeter of base: 18

height: 8

base area: 12

surface area: 216

Step-by-step explanation:

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Danielle worked three days last week for a total of 18.25 hours. She worked 6.5 hours on Monday and 5.75 hours on Wednesday. How

svet-max [94.6K]

Answer:

She worked for 6 hours on Saturday.

Step-by-step explanation:

Number of hours worked by Danielle last week = 18.25 hours

She worked for three days, Monday, Wednesday and Saturday.

Let she worked on Saturday = x hours

Therefore, total hours worked by Danielle in three days = 6.5 + 5.75 + x

And the equation will be,

6.5 + 5.75 + x = 18.25

12.25 + x = 18.25

x = 18.25 - 12.25

x = 6

Therefore, she worked for 6 hours on Saturday.

7 0

3 years ago

What fraction is equivalent 2/6

ss7ja [257]

1/3 is equivalent to 2/6 i hope this helped ^^

4 0

2 years ago

Read 2 more answers

Plsss help meee in math :(((

pishuonlain [190]

Answer:

a = 30

2a = 60

3a = 90

Step-by-step explanation:

3a + 2a + a = 180 ( Sum of angles of a triangle is 180)

6a = 180

a = 180/6

a = 30

2a = 2 x 30 =60

3a = 3 x 30 = 90

6 0

2 years ago

Relationship B has a greater rate than Relationship A. This graph represents Relationship A.

sveticcg [70]

I think the answer would be y=1.4x

4 0

3 years ago

Read 2 more answers

Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.

disa [49]

Answer:

The solutions $x^4-5x^2-36=0$ are $x=3,\:x=-3,\:x=2i,\:x=-2i$ and the x-intercepts of $y=x^4-5x^2-36$ are $x=3,\:x=-3$

Step-by-step explanation:

Finding the solutions to $x^4-5x^2-36$ means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with $u=x^2$ and $u^2=x^4$

$u^2-5u-36=0$

Solve by factoring

$\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)$

$\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)$

$\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)$

$u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)$

$\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)$

$u^2-5u-36=\left(u+4\right)\left(u-9\right)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

$\:u=-4,\:u=9$

Substitute back $u=x^2$ , solve for x

$x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)$

Apply the difference of squares formula

$x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)$

$(x-3)(x+3)(x^2+4)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

$\:x=3,\:x=-3,\:x=2i,\:x=-2i$

Because two of the solutions are complex roots the only x-intercepts are $x=3,\:x=-3$

3 0

3 years ago