y-3=3(x+1)
opening the bracket
y-3=3x+3
y=3x+3+3
equation of the line in the form y=mx+c;
y=3x+6
therefore gradient=3
parallel lines have same gradient therefore gradient of the other line is 3
y--3/x-0=3
y+3=3(x-0)
y+3=3x-0
y=3x-3.
Answer:
x= 15
Step-by-step explanation:
We can use cross products to solve this problem
7 2x+5
-- = --------
3 x
7x = 3(2x+5)
Distribute
7x = 6x +15
Subtract 6x from each side
7x-6x = 6x-6x+15
x = 15
The answer to this equation is
x= 1, -3
D the argument is not valid because the conclusion does not follow from the premises
Answer:
D
Step-by-step explanation:
