Two visits are from the fire inspector and four visits are from the health inspector in 30 days both inspectors will visit on the same day
Answer:
$3.60.
Step-by-step explanation:
If you want to tip 15%, then the total tip amount would be $2.40 plus half of that again ($1.20), which is $3.60.
Answer: 0.025
Step-by-step explanation:
Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].
The probability density function :-
Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-
![\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025](https://tex.z-dn.net/?f=%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20%5Cdfrac%7B1%7D%7B10%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%7Cx%7C%5E%7B50.5%7D_%7B50.25%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%5C%20%5B50.5-50.25%5D%3D%5Cdfrac%7B1%7D%7B10%7D%5Ctimes%280.25%29%3D0.025)
Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025
Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025
Answer:
c. We have evidence that there is a difference in population median employee satisfaction rating before and after the commission change.
Step-by-step explanation:
Pvalue is less than the alpha-level:
If the pvalue is less than the alpha-level, we have that there is sufficient evidence of the hypothesis for the population mean/median/standard deviation we are testing.
In this question:
Pvalue less than the alpha-level, so there is evidence that there is a difference in the population median. This means that the correct answer is given by option C.
