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algol13
2 years ago
13

The amount of money in a savings account after t years is represented by the function f(t)=500(1.015)^t. What does the value 500

represent in this situation?
Mathematics
1 answer:
MaRussiya [10]2 years ago
4 0

Answer:

Find out the what does the value 500 represent in this situation .

To prove

As given

The amount of money in a savings account after t years is represented by the function.

f(t)=500(1.015)^{t}

Exponential function for amount is given by .

Amount = a (1 + r)^{t}

Wher a is the initial value, r is the rate in decimal form and t is the time.

Compare the functions

f(t)=500(1.015)^{t}

and

Amount = a (1 + r)^{t}

Thus a = 500

Therefor $500 is the initial value .


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What type of exponential function is f(x)=0.6(2.4)^x ?
Vsevolod [243]

Answer:

<em>The function is of an exponential growth type</em>

<em>Rate of change is 240%</em>

Step-by-step explanation:

<u>Exponential Function</u>

The expression of an exponential function is

f(x)=c.a^{bx}

For a,b,c constants.

1.

The function will be of an exponential growth type if, when x increases, f increases. That behavior comes from the combination of the three constants a,b,c. The best approach to find that out is by taking the first derivative

f'(x)=b.c.lna.a^{bx}

Since a^{bx} is always positive, the product of b.c.lna must be positive to make f increasing. For example, if a>1 and both b and c are of the same sign, f increases for all x. If 0<a<1, then, since lna<0, the product b.c must be negative, i.e. both should have different signs

The function is expressed as

f(x)=0.6\ 2.4^x

we can see a>1, b and c are positive, so the function is of an exponential growth type.

2.

Talking about rates change of real functions takes us to the derivative function. We have already seen the derivative is dependent on all three constants and also of the value of x, so it cannot be predicted as a fixed percentage.

Now, if we picture the function as the general term of a sequence, where x can only take natural values, we can say

\displaystyle \frac{0.6(2.4)^{x+1}}{0.6(2.4)^{x}}=2.4

Each term is obtained as the previous term by 2.4. It's accurate to say the rate of change is 240%

3 0
3 years ago
Read 2 more answers
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Sidana [21]

Answer:

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8 0
3 years ago
Which is the solution for the system of linear equations below?<br><br> y= -1/3x + 3<br> y = -x + 1
tamaranim1 [39]

Answer:

x= −3 and y= 4

not sure if this is what your looking for tho

Step-by-step explanation:

7 0
3 years ago
If xy + y² = 6, then the value of dy/dx at x= -1 is<br>​
mylen [45]

Hi there!

\large\boxed{\text{At (-1, -2), }\frac{dy}{dx} = -\frac{2}{5}}}

\large\boxed{\text{At (-1, 3), }\frac{dy}{dx} = -\frac{3}{5}}}

We can calculate dy/dx using implicit differentiation:

xy + y² = 6

Differentiate both sides. Remember to use the Product Rule for the "xy" term:

(1)y + x(dy/dx)  + 2y(dy/dx) = 0

Move y to the opposite side:

x(dy/dx) + 2y(dy/dx) = -y

Factor out dy/dx:

dy/dx(x + 2y) = -y

Divide both sides by x + 2y:

dy/dx = -y/x + 2y

We need both x and y to find dy/dx, so plug in the given value of x into the original equation:

-1(y) + y² = 6

-y + y² = 6

y² - y - 6 = 0

(y - 3)(y + 2) = 0

Thus, y = -2 and 3.

We can calculate dy/dx at each point:

At y = -2: dy/dx = -(-2) / -1+ 2(-2) = -2/5.

At y = 3: dy/dx = -(3) / -1 + 2(3) = -3/5.

5 0
3 years ago
What is the equation of the line in slope-intercept form that is perpendicular to the line y = x – 2 and passes through the poin
Ostrovityanka [42]
Y= 3/4x - 2   (-2,10)= (x1,y1)
The slope is -4/3 of the perpendicular line:
Then:
y-y1=m(x-x1)
y-10=(-4/3)(x+2)
y=-(4/3)x -8/3 +10
y= -(4/3)x +22/3 (That's the answer)
5 0
2 years ago
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