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Natasha_Volkova [10]
3 years ago
11

Hellllopo please thank u

Mathematics
2 answers:
hichkok12 [17]3 years ago
6 0

Answer:

215

Step-by-step explanation:

860 grams

4 jars

=215

mixas84 [53]3 years ago
5 0
<h3>Answer:  40 grams</h3>

========================================================

Explanation:

8 jars need 1.8 kg of caster sugar.

Cut each value in half to see that 4 jars need 0.9 kg of caster sugar.

Convert 0.9 kg to grams to get 900 grams (multiply by 1000 to go from kg to grams).

Jayne needs 900 grams of caster sugar. She has 860 grams already, which means she needs an additional 900-860 = 40 grams

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Find all the zeros for each function P(x)=x^4-4x^3-x^2+20x-20
ivanzaharov [21]

Answer:

The zeros of the given polynomial function are

2,2,\pm\sqrt{5}

Step-by-step explanation:

Given polynomial is P(x)=x^4-4x^3-x^2+20x-20

To find the zeros equate the given polynomial to zero

ie., P(x)=0

P(x)=x^4-4x^3-x^2+20x-20=0

By using synthetic division we can solve the polynomial:

2_|   1     -4     -1      20      -20

       0      2     -4     -10       20

   _____________________

       1     -2      -5      10      |_0

Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:

x^3-2x^2-5x+10=0

Again using synthetic division

2_|   1     -2     -5     10      

       0      2      0    -10    

    ______________

       1      0      -5     |_0

Therefore x-2=0

x=2 is also a zero of P(x).

Now we have x^2+0x-5=0

x^2-5=0

x^2=5

x^=\pm\sqrt{5} is a zero of P(x)

Therefore the zeros are 2,2,\pm\sqrt{5}

8 0
4 years ago
Explain how the GCF is used to factor an expression?
scoundrel [369]

When factoring, it's easier to "pick out" the GCF first because it makes it simpler to factor even further. Otherwise, you will be troubled with lots of numbers and variables, so it will just get confusing.

6 0
3 years ago
I will give BRAINLIEST to whoever is correct.
attashe74 [19]
28/11.2 = 2.5

since they are similar and openly stated as parrallelograms, you know that they have a scale of the longest edge of EFGH to the longest edge of JKLM
5 0
4 years ago
an angle bisector of a triangle divides the opposite side of the triangles into segments 6cm and 4cm long. A second side of tria
Dovator [93]
From the angle bisector theorem
we can first assume the third side is x, therefore
7.4/6 = x/4
    x = 7.4 × 4/6
     x =  4.93 cm
We can also use, 
7.4/4 = x/6
      x = 7.4 ×6/4
      x = 11.1 cm
Therefore, the shortest length of the third side is 4.93 cm while the longest length is 11. 1 cm
6 0
3 years ago
The area of triangle PQR is 273 cm. Given that PQ = 12.8cm and PQR = 107°, find QR.​
storchak [24]

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8 0
3 years ago
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