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NISA [10]
3 years ago
10

Find the domain of the given function.

Mathematics
2 answers:
zubka84 [21]3 years ago
6 0
Square of quantity x plus three means : <span><span>x+3/</span>√</span>
quantity x plus eight means : <span>(x+8)</span>
quantity x minus two means : <span>(x−2)</span>

Therefore : <span>f(x)=<span><span><span>x+3 / </span>√</span><span>(x+8)</span></span>×(x−2)

</span><span>R:x≥−3</span>
marin [14]3 years ago
4 0

Answer:

[-3,2)U(2,∞)  domain of the function

Step-by-step explanation:

We have given function : f(x) =\frac{\sqrt{x+3}}{(x+8)(x-2)}

To find : The domain of the given function

Solution : Domain is where the function is defined

So, we distribute the function,

1) f(x) =\sqrt{x+3}

x\geq-3

2) f(x) =(x+8)(x-2)

x

Therefore, the domain of the function

[-3,2)U(2,∞)

or x∈real no. : -3≤x<2


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A rectangle. one side is 2x + 7 and the other is x+3
saveliy_v [14]

\large{\green}\fcolorbox{purple}{pink}{\bf{\underline{\red{\color{red}Answer}}}}

6x + 20

Step-by-step explanation:

  • <u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>

Perimeter of rectangle

  • <u>Given</u><u> </u><u>:</u><u>-</u>

Length = 2x + 7

Breadth/width = x + 3

  • <u>Solution</u><u> </u><u>:</u><u>-</u>

<em>We</em><em> </em><em>know</em><em> </em><em>that</em>

<em>\mathfrak {perimeter \: of \: rectangle =2(length + breadth) }</em>

<em>Now</em><em> </em><em>we</em><em> </em><em>will</em><em> </em><em>substitute</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>length</em><em> </em><em>and</em><em> </em><em>breadth</em>

<em>\sf  \longmapsto perimeter = 2 \{(2x + 7) + (x + 3) \} \\  \\  \\  \sf \longmapsto perimeter = 2 \{3x + 10 \} \\  \\  \\  \sf  \longmapsto perimeter = 6x + 20</em>

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2 years ago
(3mtr?)"
stepladder [879]

Answer:

81mn

Step-by-step explanation:

3 to the power of 3 is 81

7 0
3 years ago
X - y = 1 <br>Convert the equation from standard form to slope-intercept form.​
Nata [24]

Answer:

y=x-1

Step-by-step explanation:

The equation is currently in standard form which is a+b=y and slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To change the form we must move the terms around using Properties of Equality.

First, subtract 1 from both sides

x-y-1=1-1

x-y-1=0

Then, add y to both sides

x-y-1+y=0+y

x-1=y

So that is the equation in slope-intercept form with a slope of 1 and a y-intercept of -1.

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