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NISA [10]
3 years ago
10

Find the domain of the given function.

Mathematics
2 answers:
zubka84 [21]3 years ago
6 0
Square of quantity x plus three means : <span><span>x+3/</span>√</span>
quantity x plus eight means : <span>(x+8)</span>
quantity x minus two means : <span>(x−2)</span>

Therefore : <span>f(x)=<span><span><span>x+3 / </span>√</span><span>(x+8)</span></span>×(x−2)

</span><span>R:x≥−3</span>
marin [14]3 years ago
4 0

Answer:

[-3,2)U(2,∞)  domain of the function

Step-by-step explanation:

We have given function : f(x) =\frac{\sqrt{x+3}}{(x+8)(x-2)}

To find : The domain of the given function

Solution : Domain is where the function is defined

So, we distribute the function,

1) f(x) =\sqrt{x+3}

x\geq-3

2) f(x) =(x+8)(x-2)

x

Therefore, the domain of the function

[-3,2)U(2,∞)

or x∈real no. : -3≤x<2


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If and are equivalent, what is the value of x?
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3 years ago
There are 24 girls on the track team. First race2/3 girl ran.only1/4 girl ran in second race. 1/6 on third race. Hiw many more g
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10 more girls

Step-by-step explanation:

So here 2/3 of 24 ran for first race

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2 years ago
What is 73+48.7 show how you got the answer​
kotykmax [81]

Answer:

121.7

Step-by-step explanation:

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6 0
3 years ago
PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the
drek231 [11]

Answer:

1) The height of the ball from 0 to 5  seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2)  The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0
3 years ago
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