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SVETLANKA909090 [29]
3 years ago
13

Help me pleaseeeeeee

Mathematics
1 answer:
Alenkinab [10]3 years ago
3 0

everything except the last two, I think.

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The graph of y=cos⁡x is transformed to y=a cos ⁡(x−c)+d by a vertical compression by a factor of 1/3 and a translation 2 units d
rodikova [14]

ANSWER

y =  \frac{1}{3}  \cos(x)  - 2

EXPLANATION

If the graph of y=cos⁡x is transformed to y=a cos ⁡(x−c)+d by a vertical compression by a factor of 1/3 and a translation 2 units down,

then

a=1/3

and d=-2.

The 'c' is a phase shift since it is not given, it means it is zero.

Therefore the new equation is:

y=1/3cos⁡(x-0)−2

This simplifies to:

y=1/3cos⁡x−2

The correct option is C.

5 0
3 years ago
Read 2 more answers
What is the square root of 116
8090 [49]
It is 10.7703296143, but estimated it would be about 11. Hope I helped!! :)
4 0
3 years ago
Read 2 more answers
The graph of a linear function is shown on the grid
monitta

Answer: Choice A

y + 1 = -3(x+2)

=============================

Explanation:

Let's look through the answer choices.

Choices C and D show that the point (2,1) is on the line. But the graph does not show this. So we can rule out choices C and D.

With choice A, the slope is negative and choice B has a positive slope.

The answer must be choice A because the line is going downhill as we move from left to right.

--------------

A common method is to pick two points on the line and compute the slope using the slope formula

m = (y2-y1)/(x2-x1)

Once you know the slope, you would use point slope form

y - y1 = m(x - x1)

4 0
3 years ago
Can anyone pls help me in dis
barxatty [35]

Answer:

The area of building c minus the area of building b equals the area of building a might be correct?

5 0
3 years ago
Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part
katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

(26)x = 1

(50)x = 1

and:

(2^6)^x = 1

(5^0)^x = 1

Solving: (26)x = 1  and  (50)x = 1

(26)x = 1

Divide both sides by 26

x = \frac{1}{26}

(50)x = 1

Divide both sides by 50

x = \frac{1}{50}

Solving (2^6)^x = 1 and (5^0)^x = 1

(2^6)^x = 1

Express 1 as 2^0

(2^6)^x = 2^0

Remove bracket

2^{6x} = 2^0

Cancel out 2

6x = 0

Divide both sides by 6

x = \frac{0}{6}

x = 0

(5^0)^x = 1

Express 1 as 5^0

(5^0)^x = 5^0

Cancel out 5^0

x = 1

8 0
3 years ago
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