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PtichkaEL [24]
3 years ago
12

How much energy in joules will be required to raise the temperature of 50.0 g of water from 20 degrees C to 60 degree C

Chemistry
1 answer:
Paraphin [41]3 years ago
6 0

Answer: 8368 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed or released =?

c = specific heat capacity of water = 4.184J/g^0C

Initial temperature of water = T_i = 20^0C

Final temperature of water = T_f  = 60^0C

Change in temperature ,\Delta T=T_f-T_i=(60-20)^0C=40^0C

Putting in the values, we get:

Q=50.0g\times 4.184J/g^0C\times 40^0C=8368J

Thus energy in Joules required is 8368.

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Answer:

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Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

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