Question

How much energy in joules will be required to raise the temperature of 50.0 g of water from 20 degrees C to 60 degree C

Answer 1

Answer: 8368 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed or released =?

c = specific heat capacity of water = $4.184J/g^0C$

Initial temperature of water = $T_i$ = $20^0C$

Final temperature of water = $T_f$  = $60^0C$

Change in temperature ,$\Delta T=T_f-T_i=(60-20)^0C=40^0C$

Putting in the values, we get:

$Q=50.0g\times 4.184J/g^0C\times 40^0C=8368J$

Thus energy in Joules required is 8368.