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kumpel [21]
3 years ago
6

PLS HELP THIS IS TIMED

Chemistry
2 answers:
olga_2 [115]3 years ago
7 0

Answer:

The plant population has decreased. This culd reduce the other organisms as they may rely on the plants

Explanation:

hammer [34]3 years ago
4 0

Answer:

the plant population over time has decreased. this could make all other organisms above the plant population numbers decrease as well.

Explanation:

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What gas is used in freezers and fridges? ​
natta225 [31]

Answer:

Chloro-Flouro-Carbon

Explanation:

Chloro-Flouro-Carbon (CFC Gas) is used as a refrigerant in fridges and freezers.

7 0
3 years ago
How does an enzyme’s active site relate to its substrate?
Fofino [41]

Answer:

The enzyme's active site must be the mold shape of the substrate.

Explanation:

An enzyme and a substrate bind together in order to work. If the shapes of the 2 are different, they will not be able to bond together. If the shapes of the 2 fit glove-in-hand, then they will be able to bond together.

7 0
3 years ago
Read 2 more answers
Can u pls help me with this question ​
lorasvet [3.4K]

Answer:

b i im pretty sure or a

Explanation:

f y bib0f84f69g85

8 0
3 years ago
The activation energy of a certain uncatalyzed reaction is 64 kJ/mol. In the presence of a catalyst, the Ea is 55 kJ/mol. How ma
Ksivusya [100]

Answer:

About 5 times faster.

Explanation:

Hello,

In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

\frac{k_1}{k_2}=\frac{Aexp(-\frac{Ea_1}{RT} )}{Aexp(-\frac{Ea_2}{RT})}  \\\frac{k_1}{k_2}=\frac{exp(-\frac{Ea_1}{RT} )}{exp(-\frac{Ea_2}{RT})}

By replacing the corresponding values we obtain:

\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8

Such result means that the catalyzed reaction is about five times faster than the uncatalyzed reaction.

Best regards.

4 0
3 years ago
What is the molarity of a solution that contains 0.400 mol HCI in 9.79 L solutions ​
USPshnik [31]

Molarity's formula is known as: Molarity(M)=moles of solute/liters solution.

In this case we are already given moles and liters so you just have to plug the numbers into the equation.

0.400 mol HCL/9.79L solution=0.040858M

If you were to use scientific notation, the answer will be: 4.1*10^-2, but otherwise, you can just use the decimals above and round appropriately as you see fit.

6 0
3 years ago
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