Question

A percent composition analysis yields 46.7% nitrogen and 53.3% oxygen. What is the empirical formula for the compound

Answer 1

Empirical formula is the simplest ratio of whole numbers of components in a compound
calculating for 100 g of compound 
                                                     N                                   O
mass                                          46.7 g                              53.3 g
number of moles                  46.7 g / 14 g/mol                 53.3 g / 16 g/mol 
                                                  = 3.33                               = 3.33
divide by the least number of moles 
                                                3.33/ 3.33 = 1.00              3.33/3.33 = 0
number of atoms 
N - 1
O - 1
therefore empirical formula is NO