A percent composition analysis yields 46.7% nitrogen and 53.3% oxygen. What is the empirical formula for the compound

1 answer:

6 0

Empirical formula is the simplest ratio of whole numbers of components in a compound
calculating for 100 g of compound
N O
mass 46.7 g 53.3 g
number of moles 46.7 g / 14 g/mol 53.3 g / 16 g/mol
= 3.33 = 3.33
divide by the least number of moles
3.33/ 3.33 = 1.00 3.33/3.33 = 0
number of atoms
N - 1
O - 1
therefore empirical formula is NO

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