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3 years ago

37493 decreased by 8500

Mathematics

2 answers:

Amanda [17]3 years ago

8 0

37493 decreased by 8500 = <span>28993</span>

Vladimir [108]3 years ago

7 0

The answer is 28993 all u do is subtract

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WILL MARK BRAINLIEST ASAP!

musickatia [10]

Answer:

D -24/25

Step-by-step explanation:

sin(2x) = 2sin(x)cos(x)

cos(x) = ⅘

sin²(x) = 1 - cos²(x) = 1 - (⅘)²

sin²(x) = 9/25

sin(x) = -⅗

(Because 4th quadrant)

sin(2x) = 2(-⅗)(⅘)

= -24/25

4 0

4 years ago

Select all the expressions

enot [183]

Answer:

B, C, E

Step-by-step explanation:

Answer choice A):

$300 × = $75

* This answer choice represents the calculation of discount only and not the final selling price of the bicycle.

Answer choice B):

$300 × = $225

* This answer choice represents the calculation of the final selling price of the bicycle.

Answer choice C)

$300 × (1 - ) = $225

* This answer choice represents the calculation of the final selling price of the bicycle.

Answer choice D):

$300 - 1/4

*This answer choice shows an incorrect equation which neither represents the calculation of the discount nor the final selling price of the bicycle.

Answer choice E):

$300 - × $300

Applying the rule of PEMDAS,

We start with division; 1 ÷ 4 = 0.25

Then we go to multiplication; 0.25 × $300 = $75

Finally we do the subtraction; $300 - $75 = $225

* This answer choice represents the calculation of the final selling price of the bicycle.

4 0

3 years ago

Given f of x is equal to the quantity x plus 3 end quantity over the quantity x squared minus x minus 12 end quantity and g(x) =

Westkost [7]

From the given f(x) and g(x), the value of (g-f)(2)=1

Given :

The functions are

$f(x)=\frac{x+3}{x^2-x-12} \\g(x)=log_4(x)$

Lets evaluate (g-f)(2)

$(g-f)(2)=g(2)-f(2)$

To find out g(2), replace 2 for x in g(x) and then replace 2 for x in f(x)

$f(x)=\frac{x+3}{x^2-x-12} \\g(x)=log_4(x)\\x=2\\f(2)=\frac{2+3}{2^2-2-12}=\frac{5}{-10}=-\frac{1}{2} \\\\g(2)=log_4(2)=\frac{1}{2}$

Now we find g(2)-f(2)

$(g-f)(2)=g(2)-f(2)=\frac{1}{2}-\frac{-1}{2} =1$

Learn more : brainly.com/question/15038769

4 0

3 years ago

4. Meagan invests $1,200 each year in an IRA for 12 years in an account that earned 5%

Nina [5.8K]

Part A)

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]$

$\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &1200\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}$

$\bf A=1200\left[ \cfrac{\left( 1+\frac{0.05}{1} \right)^{1\cdot 12}-1}{\frac{0.05}{1}} \right]\implies A\approx 19100.55$

part B)

so, for the next 11 years, she didn't make any deposits on it and simple let it sit and collect interest, compounded annually at 5%.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\ 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$19100.55\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &11
\end{cases}
\\\\\\
A=19100.55\left(1+\frac{0.05}{1}\right)^{1\cdot 11}\implies A\approx 32668.42$

part C)

well, for 12 years she deposited 1200 bucks, that means 12 * 1200, or 14,400.

now, here she is, 12+11, or 23 years later, and she's got 32,668.42 bucks?

all that came out of her pocket was 14,400, so 32,668.42 - 14,400, is how much she earned in interest.

6 0

4 years ago

Kayla was asked to rewrite the polynomial expression x ^ 2 + 5x + 9 she rewrite the polynomial ? How could she rewrite with the

ahrayia [7]

Answer:

x²+6x+9

x²+3x+3x+9

x(x+3)+3(x+3)

=(x+3)(x+3)

8 0

3 years ago