The formula to find the volume of the composite solid is: C. V = πr²h + ⅔πr³.
<h3>How to Find the Volume of a Composite Solid?</h3>
The volume of the composite solid in the image given = Volume of cylinder + volume of hemisphere.
Volume of cylinder = πr²h
Volume of hemisphere = ⅔πr³
Therefore, formula to find the volume is: C. V = πr²h + ⅔πr³.
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Answer:
The correct option is B.
Step-by-step explanation:
The amount of money, in dollars, in a savings account after x years is given by
This above equation represents that $10000 becomes M(x) after x years at a rate of interest 3% compounded in each year.
Therefore, the value in the expression 1.03 represents that there is a 3 percent increase in the savings account each year.
So, the correct option is B. (Answer)
The first thing we must do for this case is to define variables:
x: the total mass of the chemical in the container
y: a sample of a chemical from a container
We have the following equation:
y = (3/10) x - 5 3/4
Then, for y = 39.1 we have:
39.1 = (3/10) x - 5 3/4
Clearing x:
(3/10) x = 39.1 + 5 3/4
(3/10) x = 44.85
x = (10/3) * (44.85)
x = 149.5 grams
Answer:
the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:
x = 149.5 grams.
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.
Consider the matrix multiplication below
![\left[\begin{array}{cc}a&b\\c&d\end{array}\right] \left[\begin{array}{cc}e&f\\g&h\end{array}\right] = \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7De%26f%5C%5Cg%26h%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%20e%2Bb%20g%26a%20f%2Bb%20h%5C%5Cc%20e%2Bd%20g%26c%20f%2Bd%20h%5Cend%7Barray%7D%5Cright%5D%20)
For the product to be a diagonal matrix,
a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g
Consider the following sets of values

The the matrix product becomes:
![\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C3%264%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B1%7D%7B3%7D%26-1%5C%5C-%5Cfrac%7B1%7D%7B4%7D%26%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B1%7D%7B3%7D-%5Cfrac%7B1%7D%7B2%7D%26-1%2B1%5C%5C1-1%26-3%2B2%5Cend%7Barray%7D%5Cright%5D%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-%5Cfrac%7B1%7D%7B6%7D%260%5C%5C0%26-1%5Cend%7Barray%7D%5Cright%5D)
Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.