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4 years ago

7

Aaron has a digital scale. He puts a marshmallow on The digital scale and it reads 7.2 grams. How much would you except 10 marsh

mallows to weigh? Why?

1 answer:

madreJ [45]4 years ago

4 0

Answer:

72 grams

Step-by-step explanation:

If one marshmallow weighs 7.2 all you have to do is take that times 10, which would give you 72 grams as the answer.

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hoa [83]

Answer: x=2
step by step explanation:

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3 years ago

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Given f(x) and g(x) = k⋅f(x), use the graph to determine the value of k.

Firdavs [7]

Answer:

k = -5

Step-by-step explanation:

The function f(x) passes through the points (-4,0) and (-2,2).

Therefore, the equation of the straight line is given by

$\frac{y-2}{2-0} =\frac{x-(-2)}{-2-(-4)}$

⇒ $\frac{y-2}{2} =\frac{x+2}{2}$

⇒ y = x + 4

⇒ f(x) = x + 4 ......... (1)

Now, g(x) passes through the points (-4,0) and (-2,-10).

Then the equation will be

$\frac{y-(-10)}{-10-0} =\frac{x-(-2)}{-2-(-4)}$

⇒ $\frac{y+10}{-10} =\frac{x+2}{2}$

⇒ y = - 5x - 20 = - 5 (x + 4)

⇒ g(x) = -5 (x + 4) ....... (2)

Therefore, from equations (1) and (2) we get k = -5 (Answer)

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3 years ago

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The volume of a cube is 125mm3. What is the length of its side?

Anastaziya [24]

Answer:

5

Step-by-step explanation:

All the edges of a cube have the same length, and the volume of a cube is the length of an edge taken to the third power. So the length of the edge of a cube with a volume of 125 is 5.

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3 years ago

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12) Shanaya graphed the line represented by the equation y = -2x +4 a) Write an equation

vitfil [10]

there are websites such as

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3 years ago

This figure is made up of a quadrilateral and a semicircle.

vodomira [7]

Here the figure is made up of a quadrilateral and a semi circle.

ABCD is the quadrilateral here. We will find the sides of the quadrilateral by using the distance formula.

If (x₁, y₁) and (x₂, y₂) are two points given, then the distance between two points by using distance formula is,

$d =\sqrt({ x_{1}-x_{2})^2 +( y_{1} -y_{2} )^2}$

The co-ordinate of A is (-1,2) and co-ordinate of B is (-2,-1).

So the length of side AB = $\sqrt{(-1-(-2))^2+(2-(-1))^2}$

= $\sqrt{(-1+2)^2+(2+1)^2}$ (As negative times negative is positive)

= $\sqrt{(1)^2+(3)^2} =\sqrt{1+9} =\sqrt{10}$

The co-ordinate of C is (4,-3) and D is (5,0)

The length of side CD

= $\sqrt(4-5)^2+(-3-0)^2}$

= $\sqrt{(-1)^2+(-3)^2}$

= $\sqrt{1+9} =\sqrt{10}$

So the sides AB and CD are equal.

The length of side AD

= $\sqrt{(-1-5)^2+(2-0)^2}$

= $\sqrt{(-6)^2+(2)^2} =\sqrt{36+4} =\sqrt{40}$

The length of side BC

= $\sqrt{(-2-4)^2+(-1-(-3))^2}$

= $\sqrt{(-2-4)^2+(-1+3)^2}$

= $\sqrt{(-6)^2+(2)^2}=\sqrt{36+4} =\sqrt{40}$

So the lengths of the sides AD and BC are equal.

So the quadrilateral is a rectangle whose length is $\sqrt{40}$ and width is $\sqrt{10}$ .

Area of a rectangle = length × width

= $(\sqrt{40}) (\sqrt{10})$

= $\sqrt{(40)(10)}=\sqrt{400}$

= $20 unit^2$

Now the diameter of the semicircle is the side AD = $\sqrt{40}$

So, the radius of the semi-circle = $\frac{\sqrt{40}}{2}$

= $\frac{\sqrt{(4)(10)}}{2}$

= $\frac{(\sqrt{4})(\sqrt{10})}{2}$

= $\frac{2\sqrt{10}}{2}$ = $\sqrt{10}$

Area of semi-circle = $\frac{1}{2} \pi r^2$ , where r is the radius.

= $\frac{1}{2} \pi (\sqrt{10})^2$

= $\frac{1}{2} \pi (10)$

= $\frac{(\pi)(10)}{2}$

= $\frac{10\pi}{2} = 5\pi$ = $15.7 unit^2$ ( Approximately taken to the nearest tenth)

Total area of the figure = $(20+15.7) unit^2$ = $35.7 unit^2$

We have got the required answer.

Option a is correct here.

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3 years ago

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