1. angles 4&5
2. 53 degrees
3. 35 degrees
Answer:
x<5
Step-by-step explanation:
the greater sign will firstly be changed to = for better solving so we obtain
3+9x=4(x+7)by opening bracket
3+9x=4x+28
9x-4x=28-3
5x=25
divide all through by 5x
we obtain
x=5
the greater sign change here
which is x<5
The length of JK rounded to the nearest hundredth is 4.72
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Answer:
.152
Step-by-step explanation:
only 14 but might be right
