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ladessa [460]
3 years ago
15

Evaluate the expression (ab)2 for a = 4 and b = 3. a.81 b.36 c.24 d.144

Mathematics
1 answer:
ohaa [14]3 years ago
8 0
The answer is 24.
(ab)2 = (4x3)x2 = 12x2 = 24
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Evaluate the expression:<br> 2 (m + 1) – n3 when m = -2 and n = 3
QveST [7]

Answer:

-15

Step-by-step explanation:

2 * (-4+2) = -6

-6 - 9 = -15

8 0
3 years ago
One truck delivered 3 4/5 tons of potatoes to a warehouse while another truck delivered 1/2 ton less. How many tons of potatoes
Savatey [412]
3 4/5 + (3 4/5 - 1/2) =
19/5 + (19/5 - 1/2) =
19/5 + (38/10 - 5/10) =
19/5 + 33/10 =
38/10 + 33/10 =
71/10 which equals 7 1/10 tons <==
5 0
4 years ago
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If JKL ~ MKN, find the value of x.
ella [17]

Answer: X=14

Step-by-step explanation:

7 0
4 years ago
Please help! need this As soon as possible!
Dmitry [639]

Answer:

question 1 answer:

nth term is =7n+6

9th term means n=9

So the 9th term is =7*9+6=63+6= 69.

question 2 answer: 2−4+3

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3 0
3 years ago
Read 2 more answers
Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un
erica [24]
At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1 - r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &1013\\&#10;I=\textit{initial amount}\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &0\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1- r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &1013\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &t\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


7 0
3 years ago
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