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DedPeter [7]
3 years ago
10

Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?

Chemistry
1 answer:
lesya692 [45]3 years ago
7 0
<span>Mol is the unit of amount of substance. It is equal to 6.02 x 10^23 molecules. Now, One mol of Sodium chloride (NaCl) contains 6.022x 10^23 molecules of NaCl. Also, the number atoms of both Na (sodium) and Cl (chlorine) will be equal. Similatly, One mol of Aluminium Chloride (AlCl3) contains 6.022x 10^23 molecules of (AlCl3) but the ratio of Al and Cl atoms will be 1:3</span>
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balandron [24]

Answer:

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8 0
2 years ago
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Ira Lisetskai [31]
Potassium it is the answer

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3 years ago
Y = 57.15 − 0.5 X If Y equals 5 , what is X ?<br><br> Then is Y=3, what is X?
Fiesta28 [93]

When y equals 5, x is 104.3

When y equals 3 then x is 108.3

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

y = 57.15 - 0.5x

<h3><u>If y equals 5 what is x ?</u></h3>

Substitute y = 5 in given expression

5 = 57.15 - 0.5(x)

5 = 57.15 - 0.5x

0.5x = 57.15 - 5

0.5x = 52.15

Divide both sides by 0.5

x = 104.3

Thus when y equals 5, x is 104.3

<h3><u>If y = 3 what is x ?</u></h3>

Substitute y = 3 in given expression

3 = 57.15 - 0.5(x)

3 = 57.15 - 0.5x

0.5x = 57.15 - 3

0.5x = 54.15

Divide both sides by 0.5

x = 108.3

Thus when y equals 3 then x is 108.3

7 0
3 years ago
Determine the frequency of light with a wavelength of 4.27 * 10^-7
Citrus2011 [14]

Answer:

f=7.02*10^15

Explanation:

We are supposed to find the frequency of light .

λf=c

the abow formula is the relation for frequency and wavelength.

Here c is the speed of light.

c=3*10^9m/s

Given that

λ= 4.27 * 10^-7

by substituting all this we get f as,

f=\frac{3*10^9}{4.27 * 10^-7}

f=7.02*10^15

7 0
3 years ago
PLEASE HELP ME I WILL LOVE U FOREVER
AlekseyPX

Answer:

according to me option a is the correct one

7 0
2 years ago
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