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3 years ago

What integers are closest to the square root of 54 on the number line?

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

7 0

Answer:

sqrt(54) is between 7 and 8

Step-by-step explanation:

Lets look at integers that are squared

1^2 = 1

2^2 = 2

3^2 = 9

4^2 = 16

5^2= 25

6^2 = 36

7^2 = 49

6^2 =64

54- 49 = 5 and 64 - 54 = 10

So 54 is closer to 49

so sqrt(54) is closer to the sqrt(49) = 7

sqrt(54) is between 7 and 8

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Step-by-step explanation:

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2 years ago

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3 years ago

The Flip-Flop-Alot Company makes and sells flip-flops. They have one linear function that represents the cost of producing flip-

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If we let the number of flip-flops be x in the equation and that the cost would be y ( in terms of x) and the income would be z ( in terms of x), these equations will likely intersect each other during breakeven. That is, when the total revenue that the company will gain from sales of the flip-flops just be equal with the total cost.

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3 years ago

If Karri takes a 7 question true false test and guess on every question, what is the

dusya [7]

Answer:

The probability that she gets all 7 questions correct is 0.0078.

Step-by-step explanation:

We are given that Karri takes a 7 question true-false test and guess on every question.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,........$

where, n = number of samples (trials) taken = 7 question

r = number of success = all 7 questions correct

p = probability of success which in our question is probability that

question is correct, i.e. p = 50%

Let X = Number of question that are correct

So, X ~ Binom(n = 7, p = 0.50)

Now, the probability that she gets all 7 questions correct is given by = P(X = 7)

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3 years ago

1. Four cards are drawn at random without replacement from a standard deck of 52 cards. Compute the probability that all are of

OLga [1]

Answer:

1) 10.55%

2) 30.77%

Step-by-step explanation:

52/52•39/51•26/50•13/49 = 0.105498... ≈ 10.55%

100% chance you draw a unique card on the first draw

51 cards left of which 13(3) = 39 are unique suit for your second draw

50 cards left of which 13(2) = 26 are unique suit for your third draw

49 cards left of which 13(1) = 13 are unique suit for your forth draw.

Two balls are already green

Leaves 4 red balls in a field of 13 balls

4/13 = 0.307692... ≈ 30.77%

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2 years ago