The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
Answer:
3x -y = 6
Step-by-step explanation:
When the equation of a line is given in the form ax+by=c, the perpendicular line through point (h, k) will be ...
bx -ay = bh -ak
Here, we have a=1, b=3, h=1, k=-3, so the line is ...
3x -y = 3(1) -(1(-3))
3x -y = 6
Answer:
B. 9 yards
Step-by-step explanation:
you just have to add the oak to pine and pine to end then you subtract the total of maple to end.
Answer: 36th customer.
Step-by-step explanation: 36 is divisible by both 9 and 12, and is the least common multiple.