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Akimi4 [234]
3 years ago
12

How to show the tens fact you used. write the difference. 14-6=____ 10-___=____

Mathematics
1 answer:
Dominik [7]3 years ago
8 0
This is what I believe you are looking for. 14-6=8
10-2=8
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Can I get lil help on theses please
pav-90 [236]

these are the answers is order:

10, 22, 57, 36, 42, 60, and 16,000.

Hope these helped! :D


5 0
3 years ago
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Find 54 is 90% of what number
aleksandrvk [35]
54=.9x Solve for x. x=54/.9=60
4 0
3 years ago
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How do you do 3(4y-7)=15y+6​
cestrela7 [59]

Answer:

y = 27/7

Step-by-step explanation:

Perform the indicated multiplication:

3(4y-7)=15y+6 becomes:

12y - 21 = 5y + 6

Combining like terms, we get:

7y = 27, so that y = 27/7

7 0
4 years ago
A professional soccer player kicked a ball across the field. The ball’s height, in meters, is modeled by the function graphed be
pantera1 [17]

Answer:

Hey there!

You can think of the rate of change as the slope of a quadratic function- here we see that it is 9/-3, or - 3.

Let  me know if this helps :)

6 0
3 years ago
20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0
3 years ago
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