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Margarita [4]
2 years ago
15

How do I sort them because it doesn’t quite make sense to me

Mathematics
2 answers:
german2 years ago
8 0

Answer:

can't see image

Step-by-step explanation:

tatiyna2 years ago
4 0
Higher internet rate on- initial consequences
Other 2 go to long term consequences
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A store is going out of business. Everything is
SOVA2 [1]
A. $90
150 x .40= 60
150-60=90
4 0
3 years ago
If there were 5 million births in a particular country and 3 comma 375 sets of naturally occurring​ triplets, what is the experi
IgorLugansk [536]

Answer:

Probablity =P=6.75*10^-^4

Step-by-step explanation:

The experimental probability can be defined as the ratio of the number of times any particular event has occurred to the total number of times that event has taken place.

Experimental probability = P = No. of event occurrences / total number of occurrences.

In our question statement,

No of naturally occurring triplets are = 3375

Total number of births = 5 million = 5,000,000

Putting values in equation.

P=3375/5000000

P = 0.000675\\P=6.75*10^-^4

4 0
3 years ago
A toy company produces two kites whose shapes are geometrically similar. Find the length of the missing side of the smaller kite
docker41 [41]
M=30/22,5=1,33
m=25/x=1,33. ...>x=25/1,33=18,7
5 0
3 years ago
SOMEONE PLS TELL ME IF IM RIGHT ILL MARK BRAINLIEST
Vlad1618 [11]

Answer:

u r correct

look at the picture I sent

5 0
3 years ago
Read 2 more answers
For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title
leva [86]

A good place to start is to set \sqrt{x} to y. That would mean we are looking for \sqrt{120-y} to be an integer. Clearly, y\leq 120, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since \sqrt{x} is a radical, it only outputs values from [0,\infty], which means y is on the closed interval: [0,120].

With that, we don't really have to consider y anymore, since we know the interval that \sqrt{x} is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval [0,120], which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

5 0
3 years ago
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