Explanation:
A 1 molar (M) solution will contain 1.0 GMW of a substance dissolved in water to make 1 liter of final solution. Hence, a 1M solution of NaCl contains 58.44 g
Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
I'm sorry, but I would need to see the options.
Answer:
1. Meiosis 1.
2. Meiosis 2.
3. End.
4A. The chromosome theory of inheritance states that chromosomes are the main carriers of the genetic factors responsible for inheritance.
B. Body cells have two sets of chromosomes while sex cells have one set. Therefore, when two sex cells meet, they form an embryo with two copies of each chromosomes thereby producing a body cell with the exact number of chromosomes. In essence, meiosis maintains the right number of chromosomes of body cells by creating half the number of chromosomes of sex cells.
C. Meiosis.
Explanation: