All categories

3 years ago

What are the values of the 5s in the number 54,753

Mathematics

2 answers:

Greeley [361]3 years ago

7 0

The answer is:

The 5 in tens place, the value is 50
The 5 in ten thousand, the value is 50,000

Ierofanga [76]3 years ago

4 0

The answer for the tens place is 50
and the answer for the thousand place is 50,000

You might be interested in

In a particular class, exams are worth 50% of the overall grade, quizzes are worth 30% of the overall grade, homework is worth 1

Paha777 [63]

Answer:

The student's overall grade is 85.79%

Step-by-step explanation:

Given in the question that:

Exam = 50%; Quiz = 30%, Home work = 15% and Class participation = 5%

The total giving us 100%.

A particular student scored the following;

87.9% on exams, 77.8% quiz, 90% Home work and 100% on class participation

Calculating the percentages the student had for each;

Exam total = 50*0.879 = 43.95% earned

Quiz = 30*0.778 = 23.34% earned

Home work = 15*0.9 = 13.5% earned

Class participation = 5*1 = 5% earned

Total earned = 43.95+ 23.34 + 13.5+ 5 = 85.79%

3 0

3 years ago

Convert 0.14 kilograms to grams

atroni [7]

Hey there, 0.14 kilograms is 140 grams, All I did was 0.14*1000 and that gave me 140

3 0

3 years ago

Read 2 more answers

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago

What is the standard form of <br> Y=2/5x+2

Romashka-Z-Leto [24]

The answer to your question is -10

7 0

3 years ago

Read 2 more answers

Hello there I need help.

andriy [413]

Answer:

A. 40

Step-by-step explanation:

Q1 - 40

Q2 - 65

Q3 - 80

And 90 is max

So 40 is the correct answer.

5 0

2 years ago