6 ! = 720
the definition of n ! ( n factorial ) is
n ! = n(n - 1)(n - 2) ..........× 3 × 2 × 1
6 ! = 6 × 5 × 4 × 3 × 2 × 1 = 720
Find the mean, median, and interquartile for the data set below. Round your answer to the nearest tenth. 27,16,8,5,19,14,22,31,1
slavikrds [6]
Mean: 15.92
Median: 26
interquartile range: 14-16
Answer:
a≤39/5
Step-by-step explanation:
60a - 80a ≥ -64 -92
-20a≥-156
a≤156/20
a≤39/5
X is approximately 62.23 units
Separate the square into two right triangles. Since all 4 sides of the square are congruent (equal to each other), they are all 44 units long. The Pythagorean Theorem is a^2 + b^2 = c^2, where a and b are sides of the triangle and c is the hypotenuse (longest side of the right triangle, in this case would be x).
44^2 + 44^2 = c^2
1936 + 1936 = c^2
3872 = c^2
Take the square root of both sides.
c is about 62.23
c = x, so x is around 62.23 units long
Hope this helps
If all things can be made at the same time, then it would look something like this(all numbers should be rounded down):
127 of Prep: Wreath:127/3 = 42 prepped
127 of Prep: Tree:127/14 = 9 prepped
127 of Prep: Sleigh:127/4 = 31 prepped
104 of Painting: Wreath:104/2 = 52 painted(but because only 42 were prepped, your number will be 42 still)
104 of Painting: Tree:104/3 = 34 painted(As stated above, but with only 9)
104 of Painting: Sleigh:104/17 = 6 painted(this number will overwrite the number of prepped sleighs as only 9 could be painted in the allotted time.)
133 of Firing: Wreath:133/9 = 14 ready to go
133 of Firing: Tree:133/4 = 33(but only nine were painted so the number ready to go is 9)
133 of Firing: Sleigh:133/7 = 19(but only 6 are ready to go)
Final Results: Wreath - 14
Tree - 9
Sleigh - 6
