I think c cause if he is in a relationship that’s abusive he needs to speak up before it goes way worst.
The correct answer is:Some substances keep the same molecular structure when they break down, and others do not.
Some substances change their form when they dissolve and some do not. Dissolution can sometimes be regarded as a sort of reaction between a chemical substance and water.
Usually, we can consider dissolution of a substance in water as a sort of chemical reaction for some substances. For instance, an ionic substance interacts with water to form ions. similarly, some salts become hydrolysed in water and give acidic/basic solutions as result of that.
However, some substances do not interact with water upon dissolution. They rather remain as molecular entities because they are not composed of ions.
We can see that some substances keep the same molecular structure when they break down, and others do not keep the same molecular structure when they dissolve hence it is difficult to classify dissolving as a physical or a chemical change.
brainly.com/question/1161517
Answer:
By closely observing the sedimentary rock and the presence of organic materials and mineral grains in sedimentary rocks
Explanation:
The rock cycle explains how the three types of rock are formed over time from each other.
To use a sedimentary rock to prove that the rock cycle is a valid scientific model is by, closely observing the sedimentary rock. when the sedimentary rock is closed observed the principle of superposition will be seen ( i.e. younger segments deposited on top ), the presence of organic materials and mineral grains that can be found in Igneous or Metamorphic rocks can also be seen and this shows that Sedimentary rocks pass through the rock cycle. hence this proves that the rock cycle is a valid scientific model overtime
During cell division, the DNA must be replicated, since the daughter cells need a complete set of DNA. To create TWO DNA, it must replicate. To replicate, DNA unzips, the bases pair up with a different base, and the backbone bonds.
