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evablogger [386]
3 years ago
5

Select the correct answer.

Chemistry
1 answer:
Artist 52 [7]3 years ago
3 0
I think c cause if he is in a relationship that’s abusive he needs to speak up before it goes way worst.
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Convert 682000000000 kmol to Tmol
Elena-2011 [213]

Answer:

682 teramoles

Explanation:

5 0
3 years ago
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How many grams of Cl are in 525g of CaCl2
Tema [17]

First we determine the moles CaCl2 present:

525g / (110.9g/mole) = 4.73 moles CaCl2 present 

Based on stoichiometry, there are 2 moles of Cl for every mole of CaCl2:<span>
(2moles Cl / 1mole CaCl2) x 4.73 moles CaCl2 = 9.47 moles Cl </span>

Get the mass:<span>
<span>9.47moles Cl x 35.45g/mole = 335.64 g Cl</span></span>

8 0
3 years ago
A gas containing 80% CH4 and 20% He is sent through a quart/ diffusion tube (see Figure P8.8) to recover the helium, Twenty perc
elena55 [62]

For a gas containing 80% CH4 and 20% He is sent through a quart diffusion tube, the composition is mathematically given as

%He=12.5%

%CH4=87.5%

<h3>What is the composition of the waste gas if 100 kg moles of gas are processed per minute?</h3>

Generally, the equation for the Material balance  is mathematically given as

F=R+W

Therefore

100=0.20*1000+W

W=80kmol/min

In conclusion, waste gas compose

2.0/100*100=50/100*20+%*80

Hence

%He=12.5%

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Read more about Chemical reaction

brainly.com/question/16416932

3 0
2 years ago
1.For the reaction P4 O10(s) + 6H2O(l) → 4H3PO4(aq), what mass of P
Alex17521 [72]
P₄O₁₀ + 6H₂O → 4H₃PO₄
The equation shows us that the molar ratio of
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We also know that one mole of a substance contains 6.02 x 10²³ particles. We can use this to calculate the moles of water.
moles(H₂O) = (5.51 x 10²³) / (6.02 x 10²³)
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That means moles of P₄O₁₀ = 0.92 / 6
= 0.15

Each mole of P₄O₁₀ contains 4 moles of P. 
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Mr of P = 207 grams per mol
Mass of P = 207 x 0.6
= 124.2 grams
5 0
3 years ago
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What is meant by collision theory?
Tcecarenko [31]

Answer:

The collision theory states that a chemical reaction can only occur between particles when they collide (hit each other).

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