The first dissociation for H2X:
H2X +H2O ↔ HX + H3O
initial 0.15 0 0
change -X +X +X
at equlibrium 0.15-X X X
because Ka1 is small we can assume neglect x in H2X concentration
Ka1 = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15)
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
HX + H2O↔ X^2 + H3O
8.2x10^-4 Y 8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2 = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m
B.heterogeneous mixtures
Explanation:
A heterogeneous mixture is a substance containing combination of different ingredients in different ratios.
- Heterogeneous mixtures have their constituents in different phases unlike homogeneous mixtures.
- Solutions are homogeneous of solutes and solvents that are uniformly mixed.
Heterogeneous mixtures can be subdivided into:
Gas liquid mixtures e.g aerated drinks
Liquid- solid mixtures e.g sand-sugar solution
gas solid mixtures e.g smoky air
Learn more:
Heterogeneous mixtures brainly.com/question/1446244
#learnwithBrainly
I’m confused what are you asking exactly?
Each egg has 6.022x1023 moles in it so it would just be 4 moles
Hi there!
We can use pythagorean theorem to solve this problem here. The easiest way to go about solving this problem is to use the theorem to find the hypotenuse, then dividing it by 5 to find the value of x, since the hypotenuse is 5x.
WORK:
27^2 + 36^2 = h^2 (plugging into theorem)
729 + 1296 = h^2 (squaring the numbers)
h^2 = 2025 (adding the numbers together)
hypotenuse = 49 (taking the square root of 2025)
49/5 = x (dividing 49 by 5 to find x)
x = 9.8 (dividing)
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!