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Veronika [31]
3 years ago
14

You are performing the below chemical reaction using Reagent A and Reagent B to produce Product C: A + B -> C You are using 2

moles of A and 5 moles of B. How many Equivalents of B are you using?
Chemistry
1 answer:
Luba_88 [7]3 years ago
8 0

<u>Answer:</u> The equivalents of B tat are getting used in the given chemical reaction are 2 moles.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is present in less amount and also it limits the formation of products.

Excess reagent is defined as the reagent which is present in large amount in the chemical reaction.

We are given:

Moles of A = 2 moles

Moles of B = 5 moles

For the given chemical reaction:

A+B\rightarrow C

By Stoichiometry of the reaction:

1 mole of A reacts with 1 mole of B

So, 2 moles of A will react with = \frac{1}{1}\times 2=2mol of B

As, given amount of B is more than the required amount. So, it is considered as an excess reagent.

Thus, A is considered as a limiting reagent because it limits the formation of product.

Amount of B used = 2 moles

Hence, the equivalents of B tat are getting used in the given chemical reaction are 2 moles.

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omeli [17]

Answer:

6CO2 + 6H2O → C6H12O6 + 6O2 is a balanced equation

Explanation:

Carbon, Oxygen, Hydrogen

Reactants are carbon dioxide and water, products are glucose and oxygen

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4 0
3 years ago
Which of the following molecules is amphipathic?
raketka [301]

Answer:

B) CH3(CH2)10CO2H

Explanation:

Hello,

In this case, we define amphipathic as a compound having both a hydrophilic and a hydrophobic part, for that reason, the hydrophilic part will be water-soluble (polar) whereas the hydrophobic does not (nonpolar). In such a way, some functional groups such as hydroxyl and carboxyl tend to be polar by cause of the presence of O-H bonds whereas long-carboned chains tend to be nonpolar by cause of the presence of C-H and C-C bonds.

Therefore, since A) CH3CH2OH (ethanol) and D) CH3CO2H (acetic acid) are short-carboned chains with polar groups they are largely hydrophilic whereas C) CH3(CH2)10CH3 (dodecane) is highly nonpolar, we sum up that only B) CH3(CH2)10CO2H (dodecanoic acid or lauric acid) is amphoteric as it has a long-charboned part (nonpolar) and a water-soluble part (polar).

Best regards.

7 0
4 years ago
Ions are atoms that have become___ as they have lost or gained electrons<br> whats in the gap?
GuDViN [60]

Answer:

Positively or negatively charged (im not 100% sure but the question says "as they have lost or gained electrons") because atoms that gain electrons are called anions and atoms that lose electrons are called cations. atoms losing electrons are positively charged and atoms gaining electrons are negatively charged.

I'm not sure if this helps a lot but now you know a few things about ions :)

3 0
4 years ago
A volume of 500.0 mL of 0.160 M NaOH is added to 585 mL of 0.200 M weak acid ( K a = 1.28 × 10 − 5 ) . What is the pH of the res
Hitman42 [59]

Answer : The pH of the resulting buffer is, 5.22

Explanation : Given,

K_a=1.28\times 10^{-5}

First we have to calculate the moles of NaOH\text{ and }HA

\text{Moles of }NaOH=\text{Concentration of }NaOH\times \text{Volume of solution}}=0.160M\times 0.500L=0.08mol

and,

\text{Moles of }HA=\text{Concentration of }HA\times \text{Volume of solution}}=0.200M\times 0.585L=0.117mol

The balanced chemical reaction is:

HA+(aq)+OH^-(aq)\rightarrow H_2O(l)+A^-(aq)

Moles of HA left = 0.117 mol - 0.08 mol = 0.037 mol

Moles of A^- = 0.08 mol

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (1.28\times 10^{-5})

pK_a=5-\log (1.28)

pK_a=4.89

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[A^-]}{[HA]}

Now put all the given values in this expression, we get:

pH=4.89+\log (\frac{0.08}{0.037})

pH=5.22

Thus, the pH of the resulting buffer is, 5.22

5 0
4 years ago
Cell membranes are selectively permeable. This means that A. only water can move freely across the cell membrane. B. any substan
MaRussiya [10]

Answer:

C. some substances can move freely across the cell membrane, while others must be transported.

Explanation:

6 0
3 years ago
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