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Step2247 [10]
3 years ago
7

Divide x5+15x4+54x3−25x2−75x−34 by x+8.

Mathematics
1 answer:
Wittaler [7]3 years ago
3 0

we are given

x^5+15x^4+54x^3-25x^2-75x-34

divide by x+8

we can use long division

so, we will get

Quotient=x^4+7x^3-2x^2 -9x-3

Remainder=-10

we can also write it as

\frac{x^5+15x^4+54x^3-25x^2-75x-34 }{x+8}=(x^4+7x^3-2x^2 -9x-3)-\frac{10}{x+8}..............Answer

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a zip line starts 35 feet above the ground and has one landing platform. The line is secured into the ground. what’s the height
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3 years ago
Can someone please help me with my math homework
Natali5045456 [20]
Josephine travels 32500+78000 yards at 60 mph
=110500yards
=62.78miles

time = distance/spped
time = distance/60
time=62.78/60
time=1.05 (1 hour 5 mins)

Marcus travels 78000(2)(square) +32500(2)
= 84500yards
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6 0
3 years ago
Can someone pls help?
ratelena [41]
The measure of angle 8 is 88 degrees
6 0
3 years ago
La barbería El Caleño, tiene en promedio 120 clientes a la semana a
Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

                     120 = -85.71 + b

                     120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

7 0
3 years ago
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