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3 years ago

Identify the vertical asymptotes of f(x)=x+6 over x^2-9x+18

1 answer:

7 0

$\bf \cfrac{x+6}{x^2-9x+18}
\\\\\\
x^2-9x+18=\underline{0}\implies (x-6)(x-3)=0\implies x=
\begin{cases}
6\\
3
\end{cases}$

vertical asymptotes occur, at zeros of the denominator, so long the value doesn't make the numerator zero.

so, in this case are x = 6 and x = 3.

You might be interested in

Jeremy's password is the combination of letters and numbers shown below. He

wel

Answer:

numbers:letters

5:4 (numbers:letters form)

Step-by-step explanation:

There are 5 numbers in the password and 4 letters

Hopefully this helps :)

6 0

2 years ago

Suppose that the distance, in miles, that people are willing to commute to work is an exponential random variable with a decay p

garik1379 [7]

Answer:

m = $\frac{1}{20}$
μ = 20
σ = 20

The probability that a person is willing to commute more than 25 miles is 0.2865.

Step-by-step explanation:

Exponential probability distribution is used to define the probability distribution of the amount of time until some specific event takes place.

A random variable X follows an exponential distribution with parameter m.

The decay parameter is, m.

The probability distribution function of an Exponential distribution is:

$f(x)=me^{-mx}\ ;\ m>0, x>0$

Given: The decay parameter is, $\frac{1}{20}$

X is defined as the distance people are willing to commute in miles.

The decay parameter is m = $\frac{1}{20}$ .
The mean of the distribution is: $\mu=\frac{1}{m}=\frac{1}{\frac{1}{20}}=20$ .
The standard deviation is: $\sigma=\sqrt{variance}= \sqrt{\frac{1}{(m)^{2}} } =\frac{1}{m} =\frac{1}{\frac{1}{20}} =20$

Compute the probability that a person is willing to commute more than 25 miles as follows:

$P(X>25)=\int\limits^{\infty}_{25} {\frac{1}{20} e^{-\frac{1}{20}x}} \, dx \\=\frac{1}{20}|20e^{-\frac{1}{20}x}|^{\infty}_{25}\\=|e^{-\frac{1}{20}x}|^{\infty}_{25}\\=e^{-\frac{1}{20}\times25}\\=0.2865$

Thus, the probability that a person is willing to commute more than 25 miles is 0.2865.

7 0

3 years ago

Use the data to create a scatter plot.

soldier1979 [14.2K]

I'm not sure about the given data but I plotted the scatter plot based on what I understand on how the data should be presented.

Time (years)
3, 6, 9, 12, 15, 18, 21, 24

Number of participants(x1000)
22, 25, 28, 14, 17, 20,15, 9

Attached is the scatter plot created online.
x = time (years)
y = number of participants

6 0

2 years ago

What is p(tails)? Write your answer as a percentage

Tamiku [17]

Answer: 50%

There are 2 sides, one of which is tails, so
P(tail) = 1/2 = 0.50 = 50%

6 0

2 years ago

What is the benchmark of 6/10

IceJOKER [234]

First split your model into 10 equal sections then you shade/color in 6 of them.
There it goes that is 6/10 bench mark!
~JZ
Hope it helps

3 0

2 years ago