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tresset_1 [31]
3 years ago
7

This is worth 20 points if you don't believe me look down below

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0
Well first I'd turn them all into decimals meaning the numbers would be: 
-0.75, 0.5, 0.6 repeating (basically the decimal doesn't end ex. 0.66666...), -2.3 repeating, and 1.2.

So the order would be -7/3, -3/4, 0.5, 2/3, and 1.2.

Hope this helped!
Ugo [173]3 years ago
7 0
0.5,2/3,-3/4,1.2,2.3
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The volume of a rectangular prism is 2x^3 + 9x^2 - 8x -36 with height x + 2. Using synthetic division, what is the area of the b
Luba_88 [7]

Answer:

Step-by-step explanation:

x+2=0

x=-2

-2 | 2   9    -8  -36

   |      -4  -10   36

______________

   |  2    5  -18  | 0

area= 2x²+5x-18

5 0
2 years ago
Please please please help me. I have no idea what to do
rewona [7]
We have a bunch of rectangles making up the lateral sides of this figure. They have side length 12 and height 13.

So the area of one rectangle is 12 x 13 = 156.
We have 6 of these rectangles, so our lateral area is 6(156) = 936.

The total surface area requires that we include the area of the base. To find the area of a regular polygon we take half of the product of the apothem and perimeter.

A = (1/2)*a*p

The apothem is given to be 10.39,
and the perimeter is fairly easy to calculate:
With the side length being 12, the perimeter is then 6(12) = 72.

So then the area of our base is (1/2)*10.39*72 = 374.04

So then the total surface area is the (base area) + (lateral area),
374.04 + 936 = 1310.04
3 0
3 years ago
PLEASE HELP WITH 1-3 ILL MARK U THE BRAINLIEST
sammy [17]

Answer:

1:A(-6,-1) B(-14,0) C(-11,4)

2:D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3:H(-4,1) I(-4, 6) J(0,6) K(0,1)

Step-by-step explanation:

Before we begin, lets define the transformations:

(x, y)

T(a, b) = (x+a, y +b)

Rxaxis = (x, -y)

Ryaxis = (-x, y)

r(180, 0) = (-x, -y)

D.5(1/2x, 1/2y)

R(-90, O) = (-y, x)

1. T. A(6,-1) B(14,0) C(11,4)

   Rx. A(6, 1) B(14,0) C(11,-4)

   r180 A(-6,-1) B(-14,0) C(-11,4)

2. Rx D(-12,-6) E(-4,-6) F(-6, -9) G(-10, -9)

   Ry D(12,-6) E(4,-6) F(6, -9) G(10, -9)

   D.5 D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3. Rx=1 H(-1,2) I(4, 2) J(4,-2) K(-1,-2)

   T H(1,4) I(6, 4) J(6,0) K(1,0)

   r-90 H(-4,1) I(-4, 6) J(0,6) K(0,1)

4 0
3 years ago
Harry has a penny collection with 160 pennies. He plans to increase the size of his collection by a constant term each year for
mel-nik [20]

Answer:

  • A: Harry plans to have approximately 350 pennies at the end of the second year

  • B: Harry plans to have approximately 1,200 pennies at the end of his five-year plan.

  • C: Harry plans to increase his collection by approximately 1,050 pennies over the five-year period.

  • D: Harry will add approximately 250 pennies to his collenction d during the fourth year, according to his plan.

  • E: The coordinates of the point are (3.5, 400)

  • F: Harry will need to add approximately 150 more pennies more than what he had planned by the end of the fourth year, to get back on the plan.

Explanation:

The first thing I did was to write the numbers to the grid and add the points labeled with the letter of the question with which they are related.

  • Every mark on the x-axis corresponds to 1 year.

  • Every mark of the y-axis corresponds to 200 pennies.

See the graph attached.

Question A:

The y-coordinate of the green point labeled A is about half way between 300 and 400, i.e. 350.

Then, Harry plans to have approximately 350 pennies at the end of the second year

Question B:

The green point labeled B has coordinates (5, 1200), meaning that Harry plans to have approximately 1,200 pennies at the end of his five-year plan.

Question C:

Harry started his collection with approximately 150 coins. It is the y-coordinate (the value when x = 0): (200 - 100)/2 = 150.

Thus, Harry plans to increase his collection by approximately 1,200 - 150 = 1,050 pennies over the five-year period.

Question D:

The number of peenies that Harry will add to his collection during the fourth year, according to his plan, is the difference between the number of pennies at the end of the fourth year and the end of the third year.

The green point labeled D has coordinates (4, 800) meaning that his plan is to have approximately 800 pennies.

To find the number of pennies that Harry plans to have at the end of the third year  read the y-coordinate that meets the curve when x = 3. That is approximately (600 + 500) / 2 = 550.

The difference is 800 - 550 = 250 pennies.

Therefore, Harry will add approximately 250 pennies to his collenction d during the fourth year, according to his plan.

Question E:

The blue point labeled E shows the position on the grid of the 400 pennies halfway throuhg the fourth year.

The coordinates of this point is (3.5, 400).

Question F:

According to the plan, the number of pennies at the end of the fourth year would be 800 (green point labeled D on the graph).

Then, Harry will need to add approximately 800 - 400 = 400 pennies.

According to the plan the number of coins at the end of the third year would be

But the plan was to add 800 - 550 = 250.

Thus, Harry will need to add 400 - 250 = 150 more pennies than he had planned, during the fourth year.

7 0
3 years ago
Read 2 more answers
A total of 925 tickets were sold for a game for a total of $1150. If adult tickets sold for $2 and children's tickets sold for $
Temka [501]

Answer:

  • Adult: 225
  • Children: 700

Step-by-step explanation:

If all had been children's tickets, revenue would have been $925. Actual revenue is $1150 -925 = $225 more than that. Changing a child's ticket to an adult's ticket add $1 to the revenue, so there must be $225 such changes.

The number of adult tickets is 225; the number of children's tickets is 925-225 = 700.

6 0
3 years ago
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