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3 years ago

This is worth 20 points if you don't believe me look down below

Mathematics

2 answers:

Tatiana [17]3 years ago

8 0

Well first I'd turn them all into decimals meaning the numbers would be:
-0.75, 0.5, 0.6 repeating (basically the decimal doesn't end ex. 0.66666...), -2.3 repeating, and 1.2.

So the order would be -7/3, -3/4, 0.5, 2/3, and 1.2.

Hope this helped!

Ugo [173]3 years ago

7 0

0.5,2/3,-3/4,1.2,2.3

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14 + 3х - 5 + 4х how do I solve

Varvara68 [4.7K]

Answer:

9 + 7x

Step-by-step explanation:

14 + 3х - 5 + 4х

Subtract the numbers, and add the x's together.

9 + 7x

This is the furthest the expression can be simplified.

Hope this helps :)

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Mumz [18]

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3 years ago

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An air transport association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maxim

Flura [38]

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the population mean, when the population standard deviation is not provided is:

$CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}$

The sample selected is of size, n = 50.

The critical value of t for 95% confidence level and (n - 1) = 49 degrees of freedom is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, 49}\approx t_{0.025, 60}=2.000$

*Use a t-table.

Compute the sample mean and sample standard deviation as follows:

$\bar x=\frac{1}{n}\sum X=\frac{1}{50}\times [1+5+6+...+10]=6.76\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{49}\times 31.12}=2.552$

Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:

$CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}$

$=6.76\pm 2.000\times \frac{2.552}{\sqrt{50}}\\\\=6.76\pm 0.722\\\\=(6.038, 7.482)\\\\\approx (6.0, 7.5)$

Thus, the 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

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