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lara [203]
3 years ago
11

Hello can you please help me posted picture

Mathematics
1 answer:
shutvik [7]3 years ago
6 0
First taking into account the if he buys in order.

Brian has 10 choices for the first selection of fish, 9 for the second selection and 8 for the third selection.

Thus you have 10*9*8 = 720 possible ways

However the question did not specify if it is in order. Now counting how many possible orders for each selection you can have

fish 1 , fish 2 , fish 3 or
fish 1 , fish 3 , fish 2 or 
fish 2 , fish 1 , fish 3 or
fish 2 , fish 3 , fish 1 or
fish 3 , fish 1 , fish 2 or
fish 3 , fish 2 , fish 1 or

We have 6 order.

dividing the possible ways by the order we have 720 / 60 = 120

The answer is B. 120


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Suppose that an urn contains 3 black marbles, 7 yellow marbles, and 10 green marbles. If one marble is selected, determine the p
Yuliya22 [10]

Answer:

1/2

Step-by-step explanation:

Simple probability is a ratio of the number of ways the thing we want to happen can to the total possible outcomes.

(For example, we flip a coin and want heads, but it can land on heads or tails. Our probability of getting heads is 1/2, one way to get heads over the 2 possible outcomes)

So for this problem, there's  20 possible things that CAN happen (3 + 7 + 10) and 10 ways we get what we want (a green marble).

Our probability of getting a green marble is \frac{10}{20\\}, which simplifies to \frac{1}{2}

3 0
4 years ago
Which property is being used here?<br> 5.2345 x 1 = 5.2345
Mamont248 [21]
Multiplication not to sure hope this helps :)
7 0
3 years ago
Can you please help me?​
Tanya [424]

Answer:

A, B and E

Step-by-step explanation:

A proportional relationship has the form

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3 0
3 years ago
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

8 0
3 years ago
what transformation was not done to the linear parent function f(x) to get the function (x)=-3(x+4)-7
Dominik [7]

Reflection over the x-axis, vertical shift scale factor 3, horizontal translation LEFT 3 units(opposite since there are parenthesis), vertical translation down 7 units.

3 0
3 years ago
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