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3 years ago

Hello can you please help me posted picture

Mathematics

1 answer:

shutvik [7]3 years ago

6 0

First taking into account the if he buys in order.

Brian has 10 choices for the first selection of fish, 9 for the second selection and 8 for the third selection.

Thus you have 10*9*8 = 720 possible ways

However the question did not specify if it is in order. Now counting how many possible orders for each selection you can have

fish 1 , fish 2 , fish 3 or
fish 1 , fish 3 , fish 2 or
fish 2 , fish 1 , fish 3 or
fish 2 , fish 3 , fish 1 or
fish 3 , fish 1 , fish 2 or
fish 3 , fish 2 , fish 1 or

We have 6 order.

dividing the possible ways by the order we have 720 / 60 = 120

The answer is B. 120

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3 years ago

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