Do you have the answer options? Sorry, can't answer without them ):
Part a) The true inequality statement is: 
Part b) The true inequality statement is: 
Part c) The true inequality is 
Step-by-step explanation:
We are given the two integers are -2 and -5.
Part a)
Write a true inequality statement.
The true inequality statement is: 
Part b)
Subtract-2 from each side of the inequality. Write a true inequality statement.
Subtracting -2 from each side we get:

The true inequality statement is: 
Part c)
Multiply each number by-3. Write a true inequality statement.
Multiplying -3 on both sides:

The true inequality is 
Keywords: Solving inequalities
Learn more about Solving inequalities at:
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Answer:
The volume of the irregular figure would be 102
.
Step-by-step explanation:
If you wish to make the process of calculating the volume easier, you can picture the irregular figure as two rectangular prisms: the large one on the bottom, and the smaller one appearing to protrude from the prism below it. Using this method, you only need to find the volumes of the two rectangular prisms and add the values together to get the volume for the irregular figure. The formula used to find the volume of a rectangular prism is
, where
,
, and
, represents the length, width, and height of the rectangular prism respectively. Using the formula above, the volume of the larger rectangular prism would be
, and the volume of the smaller rectangular prism would be
. So the volume of the entire irregular figure would be
.
Answer: a) -24
b) 
c) 4
Step-by-step explanation:
a) To determine the value of (fg)', use the product rule of derivative, i.e.:
(fg)'(x) = f'(x)g(x) + f(x)g'(x)
(fg)'(5) = f'(5)g(5) + f(5)g'(5)
(fg)'(5) = 6(-5) + 3(2)
(fg)'(5) = -24
b) The value is given by the use of the quotient rule of derivative:
![(\frac{f}{g})'(x)=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bf%7D%7Bg%7D%29%27%28x%29%3D%5Cfrac%7Bf%27%28x%29g%28x%29-f%28x%29g%27%28x%29%7D%7B%5Bg%28x%29%5D%5E2%7D)
![(\frac{f}{g})' (5)=\frac{f'(5)g(5)-f(5)g'(5)}{[g(5)]^2}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bf%7D%7Bg%7D%29%27%20%285%29%3D%5Cfrac%7Bf%27%285%29g%285%29-f%285%29g%27%285%29%7D%7B%5Bg%285%29%5D%5E2%7D)


c) ![(\frac{g}{f})'(5)=\frac{g'(5)f(5)-g(5)f'(5)}{[f(5)]^{2}}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bg%7D%7Bf%7D%29%27%285%29%3D%5Cfrac%7Bg%27%285%29f%285%29-g%285%29f%27%285%29%7D%7B%5Bf%285%29%5D%5E%7B2%7D%7D)


