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Sergio039 [100]
3 years ago
11

37,015 in word form please

Mathematics
2 answers:
Semenov [28]3 years ago
7 0
Thirty Seven Thousand and Fifteen
Kitty [74]3 years ago
5 0
Thirty Thousand Seven Thousand Fifteen.
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A round trip flight from Seattle, Washington to Orlando, Florida is one of the longest flights in the continental United States.
ch4aika [34]
Time out =  d/so = d/523
time back = d/sb = d/415

t = time out + time back
11 = d/523 + d/415 find common deneminator
11 = (415d + 523d)/(523*415)
11*523*415 = 415d + 523d
2387495 = 938d
d = 2545 miles 

hope this help
6 0
2 years ago
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What is 5/8 times 24hours
max2010maxim [7]
The answer is 5/8 x 24 is equal to 15 hours
8 0
3 years ago
Which is greater 2 2/3, 2.45, 2 2/5
timofeeve [1]

This is least to greatest

2 2/5 or 2.40

2.45

2 2/3

2 2/5 , 2.45 , 2 2/3

7 0
2 years ago
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The average Act score follows a normal distribution, with a mean of 21.1 and a standard deviation of 5.1. What is the probabilit
ohaa [14]

Answer:

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

\mu = 21.1, \sigma = 5.1, n = 50, s = \frac{5.1}{\sqrt{50}} = 0.7212

What is the probability that the mean IQ score of 50 randomly selected people will be more than 23

This is 1 subtracted by the pvalue of Z when X = 23. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{23 - 21.1}{0.7212}

Z = 2.63

Z = 2.63 has a pvalue of 0.9957

1 - 0.9957 = 0.0043

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

5 0
3 years ago
The tail of a kite is 1.5 feet plus twice the length of the kite. Together, the kite and tail are 15.5 ft long. Find the length
Ivan

Answer:

We know that the kite with the tail is 15 feet and 6 inches. While 6 inches is 0,50 foot, it's 15,5 feet. If the lenght of the kite is x, then:

15,5 = x + 1,5 + 2x

15,5 = 3x + 1,5     / - 1,5 (both sides)

14 = 3x             / : 3 (both sides)

x ≈ 4,66

The kite is approx .4,66 feet long. It means that the tail is about 15,5 - 4,66 = 10,84 feet long.

5 0
3 years ago
Read 2 more answers
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