OK, so just do 56 divided by 4 and you can get kenneth's tickets.
Answer:
idk how to help you with that .
Answer: 20.833mph.
Step-by-step explanation:
Using the motion Formula,
speed = distance/time.
This means:
distance = speed * time.
To find the value of "s" in the question, we have to calculate the distance both trains travelled in terms of "s" and sum it to give us 300miles.
For train A,
Speed = S miles per hour
time taken to reach current position= 7hours.
Hence, the distance travelled by train A
Distance A = 7s.
For train B,
Speed= (S + 10)miles per hour.
time taken to reach current position= 5hours (since train B left two hours after the departure of train A)
Distance = speed * time
Distance B = (S + 10) * 5
Distance B = 5s + 50.
Hence, adding both distance to sum up to 300miles, it becomes:
300 = 7s + 5s + 50
300-50 = 12s
250 = 12s
s = 20.833mph.
Answer:
3x-x+2=4
Step-by-step explanation:
Number of boys = x
Number of girls = x plus 15% of x = 1.15x
Ratio of boys to girls x:1.15x = 1:1.15 = 20:23
5(7)-7
35-7
28
The answer is: 28
