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3 years ago

12

Im absolutely clueless with part b and c

1 answer:

Elden [556K]3 years ago

7 0

Answer:

19.8 and 8/(sin(theta))+ 6/(cos(theta))

Step-by-step explanation:

If you make a table you can see that L_1 + L_2 gets larger as you increase theta prom pi/2 and decrease theta from pi/2. This means that pi/2 is the theta that will yield the smallest length for the ladder. Plugging this into L_1 + L_2 you get 19.8 (rounded to the nearest hundred)

C = 8/(sin(theta))+ 6/(cos(theta))

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3 years ago

If the area of a square plot of<br> land is 9 miles squared, what is<br> the perimeter of this land?

tatyana61 [14]

Answer:

$\huge{ \fbox{ \sf{12 \: miles}}}$

Step-by-step explanation:

Given,

Area of a square plot = 9 miles

<u>First</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>land</u>

$\boxed{ \sf{Area \: of \: a \: square \: = \: {length}^{2} }}$

$\mapsto{ \sf{9 = {length}^{2} }}$

$\mapsto{ \sf{ {length}^{2} = 9}}$

$\mapsto{ \sf{ \sqrt{ {(length)}^{2} }} = \sqrt{9} }$

$\mapsto{ \sf{length = 3 \: miles}}$

<u>Now</u><u> </u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>perimeter</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>land</u> :

$\boxed{ \sf{perimeter \: of \: a \: square = 4 \: * length}}$

$\mapsto{ \sf{perimeter \: = \: 4 \: * \: 3}}$

$\mapsto{ \sf{perimeter \: = 12 \: miles}}$

The perimeter of the land = 12 miles

Hope I helped!

Best regards! :D

~ $\text{TheAnimeGirl}$

3 0

3 years ago