All categories

3 years ago

Im absolutely clueless with part b and c

Mathematics

1 answer:

Elden [556K]3 years ago

7 0

Answer:

19.8 and 8/(sin(theta))+ 6/(cos(theta))

Step-by-step explanation:

If you make a table you can see that L_1 + L_2 gets larger as you increase theta prom pi/2 and decrease theta from pi/2. This means that pi/2 is the theta that will yield the smallest length for the ladder. Plugging this into L_1 + L_2 you get 19.8 (rounded to the nearest hundred)

C = 8/(sin(theta))+ 6/(cos(theta))

You might be interested in

What is 3 2/5 / 6 plz help!!!

Illusion [34]

Answer:

The answer is 0.56 the 6 is repeating

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How many solutions exist for the given equation?

Tpy6a [65]

Answer:

infinitely many

Step-by-step explanation:

12x + 1 = 3(4x + 1) - 2

Distribute

12x + 1 = 12x + 3 - 2

Combine like terms

12x+1 = 12x +1

Subtract 12x from each side

1 =1

Since this is always true, we have infinite solutions

4 0

2 years ago

Read 2 more answers

Please help <br> Will give BRAINLIEST

Nady [450]

5.9 m
I solved it by adding some of the numbers that were in the picture & then added the m at the end because all of the other had it

7 0

2 years ago

The rectangle below has an area of x2 + 11x + 28 square meters and a length of 2 + 7 meters.

Troyanec [42]

<h3><u>Question:</u></h3>

The rectangle below has an Área of x^2 + 11x + 28 square meters and a length of x+7 meters. What expression represents the width of the rectangle?

<h3><u>Answer:</u></h3>

The expression representing width of rectangle is (x + 4) meters

<h3><u>Solution:</u></h3>

Given that rectangle has an area x^2 + 11x + 28 square meters and a length of x + 7 meters

To find: width of the rectangle

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=\text { length } \times \text { width }$

Here area = x^2 + 11x + 28 square meters

length = x + 7 meters

<em><u>Substituting the values in given formula,</u></em>

$\begin{array}{l}{\text { width }=\frac{x^{2}+11 x+28}{x+7}} \\\\ {\text { width }=\frac{x^{2}+4 x+7 x+28}{x+7}} \\\\ {\text { width }=\frac{x(x+4)+7(x+4)}{x+7}} \\\\ {\text { width }=\frac{(x+4)(x+7)}{x+7}}\end{array}$

Cancelling (x + 7) on numerator and denominator,

$\text { width }=(x+4)$

Thus expression representing width of rectangle is (x + 4) meters

3 0

3 years ago

Given f(x) = 2x + 2, solve for x when f(x) = -4<br><br><br>Anyone know the answer?

Allushta [10]

X=-2 I’m pretty sure that’s the answer! :)

3 0

3 years ago