Answer:
At point A, the cart has high potential energy. At point b, the cart is pulled down by gravity. At point c, the cart gains its highest kinetic energy. At point d, the cart returns back to the same state but with lower potential energy.
When a charged particle—such as an electron, proton or ion—is in motion, magnetic lines of force rotate around the particle.
1 to 3 S, for the bottom question, and 1 s for the top questions (guessing, sorry)
Answer:
The angle of launch is 52.49 Degree.
Explanation:
The Range R and Height H of a thrown object is calculated using the formula,
R=V₀² sin(2φ)/g
H=V₀²sin²(φ)/g
From these equations it can be written,
V₀²=R g/ sin(2φ)
V₀²=H g/ sin²(φ)
These values are equal so it can be written by equating these equations,
R g/sin(2φ)=H g/sin²(φ)
tan(φ)= 2H/R
Given H=72.3 m and R=111 m, the angle of launch is,
tan(φ)= 2*72.3/111
φ= 52.49 Degree.
Check out other solutions,
brainly.com/question/1495042
#SPJ10
Answer:
The maximum velocity is 2.23 m/s.
Explanation:
Given that,
Deceleration = 50 cm/s²
Range = 5 m
Let the maximum speed of robot is
We need to calculate the maximum velocity
Using equation of motion
Where, v = maximum velocity
U = initial velocity
s = distance
Put the value into the formula
Hence, The maximum velocity is 2.23 m/s.