Question

An object possessing an excess of 6.0x10^6 electrons has a net charge of

Answer 1

A single electron has a charge of
$e=-1.6 \cdot 10^{19}C$
Therefore, if we have an excess of $N=6.0\cdot10^6$ electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
$Q=Ne=(6.0\cdot10^6)(-1.6 \cdot 10^{-19}C)=9.6 \cdot 10^{-13}C$