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r-ruslan [8.4K]
4 years ago
7

An object is electrically charged if the amounts of positive and negative charge it contains are not _______.

Physics
2 answers:
Naddik [55]4 years ago
4 0
Equal bc it’s neutral
zlopas [31]4 years ago
3 0

Answer:oops

Explanation:

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A constant force of 2.5 N to the right acts on a 4.5 kg mass for 0.90 s.
Alborosie

Answer:

(a) v_f=0.5\frac{m}{s}

(b) v_f=-11\frac{m}{s}

Explanation:

(a) Since a constant external force is applied to the body, it is under an uniformly accelerated motion. Using the following kinematic equation, we calculate the final velocity of the mass  if it is initially at rest(v_0=0):

v_f=v_0+at\\v_f=at(1)

According to Newton's second law:

F=ma\\a=\frac{F}{m}(2)

Replacing (2) in (1):

v_f=\frac{F}{m}t\\v_f=\frac{2.5N}{4.5kg}(0.9s)\\v_f=0.5\frac{m}{s}

(b) In this case we have v_0=-11.5\frac{m}{s}. So, we use the final velocity equation:

v_f=v_0+at\\v_f=v_0+\frac{F}{m}t\\v_f=-11.5\frac{m}{s}+\frac{2.5N}{4.5kg}(0.9s)\\v_f=-11\frac{m}{s}

8 0
3 years ago
HELP ME ASAP!!!! PIC IS DOWN BELOW!
vagabundo [1.1K]
I think it is B Because it sounds like the best choice
7 0
3 years ago
Read 2 more answers
Determine the maximum theoretical speed that may be achieved over a distance of 66 m by a car starting from rest, knowing that t
My name is Ann [436]

Answer:

v=32.49 m/s

Explanation:

Given that

Distance ,d= 66 m

Initial speed of the car ,u = 0 m/s

Coefficient of friction ,μ = 0.8

Lets take the total mass of the car = m

The acceleration of the car is given as

a = μ g                               ( g= 10 m/s² )

Now by putting the values in the above equation we get

a= 0.8 x 10 m/s²

a= 8 m/s²

We know that ,final speed is given as

v²= u ²+ 2 a d

Now putting the value

v²=0² + 2 x 8 x 66

v²= 1056

v=32.49 m/s

3 0
3 years ago
A ball is thrown up into the air with an initial velocity of 18 m/s. A) How high does the ball go? B) Calculate the time needed
kaheart [24]

Answer:

B) t = 1.83 [s]

A) y = 16.51 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} =v_{o} -g*t

where:

Vf = final velocity = 0

Vo = initial velocity = 18 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.

A) The maximum height is reached when the final velocity of the ball is zero.

0 = 18 - (9.81*t)

9.81*t = 18

t = 18/9.81

t = 1.83 [s], we found the answer for B.

Now using the following equation.

y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\

where:

y = elevation [m]

Yo = initial elevation = 0

y = 18*(1.83) - 0.5*9.81*(1.83)²

y = 16.51 [m]

7 0
3 years ago
Theories and Laws.
Scilla [17]
Laws and theories are similar in that they are both scientific statements that result from a tested hypothesis and are supported by scientific evidence.
6 0
3 years ago
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