All categories

3 years ago

How many squares for three traits?

1 answer:

Studentka2010 [4]3 years ago

4 0

You just need one square but with 16 little boxes
list out all the possible combination for each set of traits
add then to the each side of the box and match them up

You might be interested in

Scientific notation of 86400

Mandarinka [93]

8.64×10^4

this is 86400 in scientific notation

3 0

3 years ago

Read 2 more answers

A planet has a surface temperature of 95.0 K and an atmospheric pressure of 1.60 atm. If 4.87 L of atmosphere has a mass of 28.6

mr Goodwill [35]

Answer:

M=28.88 gm/mol

Explanation:

Given that

T= 95 K

P= 1.6 atm

V= 4.87 L

m = 28.6 g

R=0.08206L atm .mol .K

We know that gas equation for ideal gas

P V = n R T

P=Pressure , V=Volume ,n=Moles,T= Temperature ,R=gas constant

Now by putting the values

P V = n R T

1.6 x 4.87 = n x 0.08206 x 95

n=0.99 moles

We know that number of moles given as

$n=\dfrac{m}{M}$

M=Molar mass

$n=\dfrac{m}{M}$

$0.99=\dfrac{28.6}{M}$

M=28.88 gm/mol

3 0

3 years ago

Jason knows that the equation to calculate the period of a simple pendium T=2π√L/8, where T is the period, L is the length of th

erik [133]

Answer: L can be expressed in terms of g and f as

L = g/(2πf)^2

Explanation: Please see the attachments below

3 0

3 years ago

For a closed system, entropy Group of answer choices may be produced within the system. all of the answers are correct. may be t

wolverine [178]

Answer:

The answer is: all of the answers are correct.

Explanation:

Entropy is defined as the magnitude of the irreversibilities of a process. Entropy is the disorder of molecules within a system. If the system is closed, entropy is produced if the process is irreversible. If the system is subjected to expansions or energy transfer, the entropy increases.

A process is reversible if the system and its surroundings are returned to their initial states. In a quasi-static process it is characterized by being a reversible process in which there are no irreversibilities. The entropy in this system is constant in the system.

6 0

3 years ago

Two skaters collide and grab on to each other on frictionless ice. One of them, of mass 66.0 kg , is moving to the right at 2.00

ivann1987 [24]

Answer:

The velocity of skaters after collision is 0.55 m/s and they are moving to the left

Explanation:

Consider m₁ and m₂ are the masses of two skaters and their initial velocity be v₁ and v₂ respectively.

Consider the velocity along right direction as positive while negative for left direction.

According to the problem,

Mass of first skater, m₁ = 66.0 kg

Mass of second skater, m₂ = 75.0 kg

Velocity of first skater, v₁ = + 2.00 m/s

Velocity of second skater, v₂ = -2.80 m/s

Since, the two skaters grab each other after collision. Hence, they are moving with same final velocity v.

Applying conservation of linear momentum,

Momentum before collision = Momentum after collision

m₁v₁ + m₂v₂ = (m₁+m₂)v

Substitute the suitable values in the above equation.

66 x 2 - 75 x 2.8 = (66 + 75 )v

$v= \frac{-78}{141}$

v = -0.55 m/s

The negative sign denotes that both the skaters are moving in the left direction.

6 0

3 years ago