Answer:14 m/s
Explanation:
Kinetic energy(ke)=175J
Momentum(M)=25kgm/s
Speed=v
Mass=m
Ke=(m x v x v)/2
175=(mv^2)/2
Cross multiply
175 x 2=mv^2
350=mv^2
Momentum=mass x velocity
25=mv
m=25/v
Substitute m=25/v in 350=mv^2
350=25/v x v^2
350=25v^2/v
v^2/v=v
350=25v
v=350/25
v=14 m/s
Explanation:
option A is the correct answer, if the gravitational acceleration is taken 10m/s²(rounding of 9.8/ms²).
hope this helps you.
For this case, what we must do is to rewrite these measurements in the same unit in order to compare them.
By writing the measurements in meters we have:



Therefore, physically the correct measure is:

Answer:
the length of a student's textbook most likely is:
30 centimeters
Answer:
Option B
Change in entropy of the process is 
Explanation:
The entropy of a system is a measure of the degree of disorderliness of the system.
The entropy of a system moving from process 1 to 2 is given as

recall from first law, 
hence we have, 
since the process is isothermal, 
this gives us 
integrating within the limits of 1 and 2, will give us

also from ideal gas laws,
hence we have 
This makes the correct option B
Answer:
v = √[gR (sin θ - μcos θ)]
Explanation:
The free body diagram for the car is presented in the attached image to this answer.
The forces acting on the car include the weight of the car, the normal reaction of the plane on the car, the frictional force on the car and the net force on the car which is the centripetal force on the car keeping it in circular motion without slipping.
Resolving the weight into the axis parallel and perpendicular to the inclined plane,
N = mg cos θ
And the component parallel to the inclined plane that slides the body down the plane at rest = mg sin θ
Frictional force = Fr = μN = μmg cos θ
Centripetal force responsible for keeping the car in circular motion = (mv²/R)
So, a force balance in the plane parallel to the inclined plane shows that
Centripetal force = (mg sin θ - Fr) (since the car slides down the plane at rest, (mg sin θ) is greater than the frictional force)
(mv²/R) = (mg sin θ - μmg cos θ)
v² = R(g sin θ - μg cos θ)
v² = gR (sin θ - μcos θ)
v = √[gR (sin θ - μcos θ)]
Hope this Helps!!!