Answer:
B. It begins to rotate counterclockwise
Explanation:
It can happen that the merry-go-round remains at rest in the case when the person is standing on the axle of the merry go round whose axis is fixed to some rigid support, but here the person is standing at the center of the merry-go-round not at the axle hence the according to the conservation of angular momentum. Angular momentum is given as:

for the conservation of momentum

where:
moment of inertia of the merry-go-round
angular velocity of the merry-go-round
moment of inertia of the bicycle wheel
angular velocity of the wheel
As the person tries to stop the wheel which is rotating then the person feels an opposing force which tries to moves the whole system in its direction.
As electrons move through the conductor, some collide with atoms, other electrons, or impurities in the metal.
Answer:
The speed on boat in still water is
and the rate of the current is 
Explanation:
Since speed , 
Therefore speed of motor boat while traveling upstream is

and speed of motor boat while traveling downstream is
Let speed of boat in still water be
and rate of current be 
Therefore
----(A)
and
------(B)
Adding equation (A) and (B) we get

=>
------(C)
Substituting the value of
in equation (A) we get

Thus the speed on boat in still water is
and the rate of the current is 
Answer:
The answer here would be its "Magnitude".
Answer:
11250 N
Explanation:
From the question given above, the following data were obtained:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
Friction and normal force are related by the following equation:
F = μR
Where:
F is the frictional force.
μ is the coefficient of static friction.
R is the normal force.
With the above formula, we can calculate the frictional force acting on the car as follow:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
F = μR
F = 0.75 × 15000
F = 11250 N
Therefore, the frictional force acting on the car is 11250 N