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3 years ago

What is the formula for the ionic compound formed by magnesium and iodine?

Chemistry

1 answer:

MrMuchimi3 years ago

7 0

The compound that is formed is: MgI2

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What can u say about the sizes of all the atoms in a piece of carbon

vlada-n [284]

Answer:

all atoms must have 6 protons to be a carbon atom

Explanation:

brainliest?

4 0

2 years ago

Americans eat too much salt (NaCl). A healthy adult should eat no more than 6 g of salt in one day. Use this information to answ

Rufina [12.5K]

Answer:

a. 58.5 g/mol

b. 0.1 mol

Explanation:

The molar mass of Na is 23.0 g/mol. The molar mass of Cl is 35.5 g/mol. The molar mass of NaCl is:

M(Na) + M(Cl) = 23.0 g/mol + 35.5 g/mol = 58.5 g/mol

b. A healthy adult should eat no more than 6 g of salt in one day. The moles corresponding to 6 g of NaCl are:

6 g × (1 mol/58.5 g) = 0.1 mol

7 0

3 years ago

How many molecules (not moles of nh3 are produced from 5.01×10?4 g of h2?

Irina-Kira [14]

2,02g ------- 6,02×10²³
5,01×10⁴g --- x

$x=\frac{5,01*10^{4}g*6,02*10^{23}}{2,02g}=14,93*10^{27}$

N₂ + 3H₂ ⇒ 2NH₃
1mol : 3mol : 2mol
18,06×10²³ : 12,04×10²³
14,93×10²⁷ : y

$y=\frac{14,93*10^{27}*12,04*10^{23}}{18,06*10^{23}}\approx9,95*10^{27}$

5 0

2 years ago

Va rog ! urgent! E pt chimie

n200080 [17]

Answer:

An element

It stays shiny

Explanation:

Pure Gold is an element.

An element is a distinct substance that cannot be split-up into simpler substances. Such substances consists of only one kind of atom.

There are over a hundred elements known to date.

As an element, Gold is classified as a metal due to its very unique set of properties.

One of the indicator that gold does not react with oxygen is that it stays shiny. It does not give rusty look when exposed to air.

Substances that combines with oxygen have a rusty look or change appearance when expose to air. For example, iron.

5 0

2 years ago

Predict the boiling point of water at a pressure of 1.5 atm.

Lina20 [59]

Answer:

100.8 °C

Explanation:

The Clausius-clapeyron equation is:

$ln\frac{P_{1} }{P_{2}} =$ -Δ $\frac{H_{vap}}{r} (\frac{1}{T_{2}}-\frac{1}{T_{1}} )$

Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'

Isolating for T2 gives:

$T_{2}=(\frac{1}{T_{1}} -\frac{Rln\frac{P_{2}}{P_{1}} }{Delta H_{vap}}$

(sorry for 'deltaHvap' I can not input symbols into equations)

thus T2=100.8 °C

7 0

2 years ago