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3 years ago

What are the physical and chemical properties of iron oxide

1 answer:

5 0

Answer: The physical properties of iron oxide are that it is an odorless, red-brown solid, and that it is insoluble. Depending on the chemical formula, one of the chemical properties is its combustibility. If the chemical formula is Fe2O3, it is not combustible. If the formula is FeO, it is readily combustible.

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A redox reaction employed in an electrochemical cell has a negative . Which statement is true? a) E∘cell is positive b) K>1 E

krok68 [10]

Answer:

d. K<1 E∘cell is negative

Explanation:

Since E⁰ = negative , ΔG = -nFE⁰ = -nF -ve = +ve.

Also, ΔG = -RTlnK

K = exp(-RTΔG)

Since ΔG = +ve, -RTΔG = -ve

K = 1/exp(RTΔG) < 1.

So our answer is E⁰ cell is negative and K < 1

5 0

3 years ago

If the distance between two objects is decreased to - of the original

Charra [1.4K]

Answer:

The new force will be \frac{1}{100} of the original force.

Explanation:

In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.

That said, let's say that our equation for the initial force is:

$F = G\frac{m_1m_2}{R^2}The problem states that the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R$

And the force at this distance would be written in terms of the same equation:

$F_2 = G\frac{m_1m_2}{R_2^2}$

Find the ratio between the final and the initial force:

$\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}$

Substitute the value for the final distance in terms of the initial distance:

$\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}$

Simplify:

$\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}$

This means the new force will be \frac{1}{100} of the original force.

8 0

3 years ago

Write a balanced half-reaction for the oxidation of aqueous hydrazine N2H4 to gaseous nitrogen N2 in basic aqueous solution

Zigmanuir [339]

Answer:

N2H2(aq) + 2OH^-(aq) ----------> N2(g) + 2H2O(l) + 2e

Explanation:

Hydrazine is mostly used in thermal engineering as an anticorrosive agent. Hydrazine can be oxidized in aqueous solution as shown in the equation above. Oxidation has to do with loss of electrons and increase in oxidation number.

The oxidation number of nitrogen in the equation increased from -1 in hydrazine on the lefthand side of the reaction equation to zero in nitrogen on the right hand side of the reaction equation. Two electrons were lost in the process as shown.

7 0

3 years ago

Give two different conditions under which long chain hydrocarbons may be cracked.

sammy [17]

In thermal cracking, high temperatures (typically in the range of 450°C to 750°C) and pressures (up to about 70 atmospheres) are used to break the large hydrocarbons into smaller ones. Thermal cracking gives mixtures of products containing high proportions of hydrocarbons with double bonds - alkenes.

5 0

3 years ago

What is the molarity of na+ in a solution of nacl whose salinity is 5.6 if the solution has a density of 1.03 g/ml?

pantera1 [17]

Salinity has units of grams NaCl or salt per kilogram solution. We can use the density given and the molar mass of the salt to convert from salinity to molarity. We do as follows:

( 5.6 g / kg ) ( 1.03 kg / L ) ( 1 mol / 58.44 g ) = 0.0987 mol NaCl / L

8 0

3 years ago